数组内的php条件

Question

在下面的代码中，当 {VarName} 为空（空白或空）时，我需要能够设置不同的 where 条件。

数组定义中是否可以有 if 条件？ 或者，我可以在 sql 查询中进行验证吗？

$col["editoptions"] = array(
             "value"=>$str, 
             "onchange" => array(
              array(
              "sql"=> "select distinct place as k, place as v from mytable                                       
                      WHERE Name = '{VarName}' 
                      AND Area = '{VarArea}'
                      ORDER BY place",
              "update_field" => "Localidade" )));

Answer 1

您可以在数组定义中使用三元，如下所示：

condition ? value-if-true : value-if-false

例如，

1 == 1 ? 'yes' : 'no'; // evaluates to 'yes'

所以在你的情况下：

$col["editoptions"] = array(
    "value"=>$str, 
    "onchange" => array(
        array(
            "sql"=> empty($VarName) ?
                "YOUR ALTERNATIVE SQL HERE" : 
                "select distinct place as k, place as v from mytable                                       
                      WHERE Name = '{VarName}' 
                      AND Area = '{VarArea}'
                      ORDER BY place",
              "update_field" => "Localidade"
        )
    )
);

为了使您的数组定义更整洁，您应该考虑将您的 SQL 放在一个变量中并在数组 def 中引用该变量：

$sql = empty($VarName) ?
    "YOUR ALTERNATIVE SQL HERE" : 
    "select distinct place as k, place as v from mytable                                       
        WHERE Name = '{VarName}' 
        AND Area = '{VarArea}'
        ORDER BY place";
$col["editoptions"] = array(
    "value"=>$str, 
    "onchange" => array(
        array(
            "sql" => $sql,
            "update_field" => "Localidade"
        )
    )
);

Answer 2

就像@Matt 说的，你可以像下面这样构建内部数组。

$VarName1 = null;

$col["editoptions"] = array(
    "value"=> 'value', 
    "onchange" => array(
     array(
     "sql"=> "select distinct place as k, place as v from mytable                                       
             WHERE Name = " . ( $VarName1 ? "'{VarName1}'" : "'{VarName2}'" ) .     
             "AND Area = '{VarArea}'
             ORDER BY place",
     "update_field" => "Localidade" )));

如果您使用另一个变量中的条件在字符串中生成 sql 会更好，如下所示以便于维护。

$sql = "select distinct place as k, place as v from mytable                                      
WHERE Name = ";
if( $VarName1 ){
    $sql .= "'{VarName1}'";
}
else{
    $sql .= "'{VarName2}'";
}
$sql .=   "AND Area = '{VarArea}' ORDER BY place";