如何使用云功能删除 Firestore 中的文档

Question

我想检查在 firestore 中创建的文档，以确保公开可见的字段中没有包含脏话。 我希望能够在检测到包含脏话后删除该帖子。 为此，我正在尝试使用 firebase 云功能：

// Package used to filter profanity
const badWordsFilter = require('bad words-list');

// The Cloud Functions for Firebase SDK to create Cloud Functions and setup triggers.
const functions = require('firebase-functions');

// The Firebase Admin SDK to access Cloud Firestore.
const admin = require('firebase-admin');
admin.initializeApp();

export const filterBadWords =
  functions.firestore.document("posts/{userId}/userPosts/{postId}").onCreate((snapshot, context) => {
    const message = snapshot.data.val();

    // Check if post contains bad word
    if (containsSwearwords(message)) {
      //This is where I want to remove the post.
      //What do I put here to delete the document?
    }
  })

// Returns true if the string contains swearwords.
function containsSwearwords(message: any) {
  return message !== badWordsFilter.clean(message);
}

数据库结构：

-posts(Collection)
   |
   +---{userID} (Document)
          |
          +---userPosts (collection)
                  |
                  +---{Documents to be checked} (Document)
                  |
                  +-Url1(field)
                  +-Url2(field)
                  +-string1(field)<- check this field for swear
                  +-string2(field)<- check this field for swear

云函数是使用 javascript 编写的

Answer 1

您可以使用ref来获取DocumentReference并调用delete() ：

functions.firestore.document("posts/{userId}/userPosts/{postId}").onCreate(
  async (snapshot, context) => {
    const message = snapshot.data.val();

    // Check if post contains bad word
    if (containsSwearwords(message)) {
      await snapshot.ref.delete();
    }
  }
)

如果他们之后可以编辑他们的帖子，您应该概括此功能并将其添加到onUpdate触发器中

Answer 2

这个答案会很简短，但不需要解释。 这是代码（对于 swift，我不是 100% 确定如何在 js 中执行此操作）

迅速：

db.collection("cities").document("DC").delete() { err in
    if let err = err {
        print("Error removing document: \(err)")
    } else {
        print("Document successfully removed!")
    }
}

这可能适用于 javascript，而不是 100% 确定

db.collection("cities").doc("DC").delete().then(function() {
    console.log("Document successfully deleted!");
}).catch(function(error) {
    console.error("Error removing document: ", error);
});

希望能帮助到你