Criteria API（规范 JPA）加入

Question

这是我目前的模型

@Entity
public class A {

@Id
private Long id;

String name;

...

@Entity
public class B {

@Id
private Long id;

@ManyToOne()
@JoinColumn(name = "a_id")
private A a;

@ManyToOne()
@JoinColumn(name = "c_id")
private C c;

...

@Entity
public class C {

@Id
private Long id;

private String status;

我想要一个 A 类的列表，其中 C 类的状态为“ACTIVE”，使用带有显式 JOIN 的 Criteria API作为以下示例与IN

Subquery<B> subQB = query.subquery(B.class);
Root<B> rootB = subQB.from(B.class);
subQB.select(rootB.get("c").get("id"))
                      .where(builder.equal(rootB.get("c").get("status"), "ACTIVE"));        
predicates.add(root.get("id").in(subQB)); // root is class A

谢谢你的帮助。

Answer 1

如果没有实际运行的数据库，它不应该类似于

CriteriaBuilder cb = em.getCriteriaBuilder();

// Because the result is "A"
CriteriaQuery<A> q = cb.createQuery(A.class);

// Start from B
Root<B> bRoot = q.from(B.class);

// Path from B to A, as local variable to increase readability
Path<A> aPath = bRoot.get("a");

// Path from B to C and to C's status, as local variable to increase readability
Path<C> cPath = bRoot.get("c");
Path<String> cStatusPath = cPath.get("status");

// SELECT A FROM B WHERE B.C.Status = "ACTIVE"
q.select(aPath)
  .where(cb.equal(cStatusPath, "ACTIVE"));

编辑：

显式连接应该与第一个解决方案非常相似，所以

CriteriaBuilder cb = em.getCriteriaBuilder();

// Because the result is "A"
CriteriaQuery<A> q = cb.createQuery(A.class);

// Start from B
Root<B> bRoot = q.from(B.class);

// Path from B to A, as local variable to increase readability
Path<A> aPath = bRoot.get("a");

// Join from B to C and to C's status, as local variable to increase readability
Join<B, C> cJoin = bRoot.join("c");
Path<String> cStatusPath = cJoin.get("status");

// SELECT A FROM B WHERE B.C.Status = "ACTIVE"
q.select(aPath)
  .where(cb.equal(cStatusPath, "ACTIVE"));