Typescript 异步 function 无 Promise 类型

Question

当您查看 typescript async function 时，您可以清楚地看到async和Promise<type>的冗余。

public async test(): Promise<string> {
  return "Test";
}

有没有办法配置 typecrypt 来处理没有Promise<T>类型的异步类型？ T ：

public async test(): string {
  return "Test";
}

当我试图跳过Promise< >时，我得到了这个： The return type of an async function or method must be the global Promise<T> type. Did you mean to write 'Promise<number>'?ts(1064) The return type of an async function or method must be the global Promise<T> type. Did you mean to write 'Promise<number>'?ts(1064)

Question is about how to avoid writing boilerplate. We know that async fn() will always return a Promise, so why do I have to write Promise<T> Question is about how to avoid writing boilerplate. We know that async fn() will always return a Promise, so why do I have to write Promise<T> - @josh3736

Answer 1

TypeScript 存储库中已经有这样的建议：建议我同意评论者的意见，即这种“功能”可能会造成混淆和危险。