如何将对象属性复制到其他对象，然后从数组中删除该对象？

Question

如果对象名称相同，我想复制source属性，然后从数组中删除该对象。 我该如何实施？

const data = [
    {name: "name1", source: "source1"},
    {name: "name1", source: "source2"},
    {name: "name2", source: "source3"},
    {name: "name3", source: "source4"},
    {name: "name4", source: "source5"},
]

预期结果

[
  {name: "name1", source: "source1, source2"},
  {name: "name2", source: "source3"},
  {name: "name3", source: "source4"},
  {name: "name4", source: "source5"},
]

Answer 1

使用Array.prototype.reduce ，你可以按值name键值，并合并source相同的键值name键。

 const data = [ {name: "name1", source: "source1"}, {name: "name1", source: "source2"}, {name: "name2", source: "source3"}, {name: "name3", source: "source4"}, {name: "name4", source: "source5"}, ]; const groupBy = data.reduce((acc, cur) => { acc[cur.name] ? acc[cur.name].source += `,${cur.source}` : acc[cur.name] = cur; return acc; }, {}); const output = Object.values(groupBy); console.log(output);