[英]How to make sql nested/sub query in PHP
我正在努力在我的 php 代码中实现 SQL 查询。
查询:
select template_id, min(created_at) as created_at from (
select distinct
root_template_id as template_id,
date_created as created_at,
response_id as response_id
from db.score
inner join db.users ON db.score.supplier_id = db.users.old_id
inner join db.acc ON db.acc.user_id = db.users.id
where db.acc.account_id = 25) as T
group by template_id
我只能准备这部分:
$query = DB::table('score')
->selectRaw('DISTINCT root_template_id as template_id, date_created as created_at, response_id')
->join('users', 'score.supplier_id', '=', 'users.old_id')
->join('acc', 'acc.user_id', '=', 'users.id')
->whereIn('acc.account_id', $request->id)
它可以工作,但它只负责嵌套部分,如果我可以这样调用它,则负责子查询。 有人可以分享任何想法吗?
DB::table()
通常以字符串形式接收表名,但它也可以接收Closure
或Illuminate\\Database\\Query\\Builder
实例,因此这应该可以为 Laravel 从子查询中选择:
DB::table(function ($query) use ($request) {
$query->selectRaw('DISTINCT root_template_id as template_id, date_created as created_at, response_id')
->from('score')
->join('users', 'score.supplier_id', '=', 'users.old_id')
->join('acc', 'acc.user_id', '=', 'users.id')
->whereIn('acc.account_id', $request->id)
}, 'T')
->select([
'template_id',
DB::raw("MIN(created_at) AS created_at"),
])
->groupBy('template_id')
->get();
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