[英]How to pass parameters to laravel factory in database seeder?
是否可以将数据从播种机传递到工厂?
这是我的PictureFactory
:
class PictureFactory extends Factory{
protected $model = Picture::class;
public function definition($galleryId = null, $news = false){
if (!is_null($galleryId)){
$galley = Gallery::find($galleryId);
$path = 'public/galleries/' . $galley->name;
$newsId = null;
}
if ($news){
$path = 'public/newsPicture';
$newsId = News::all()->random(1);
}
$pictureName = Faker::word().'.jpg';
return [
'userId' => 1,
'src' =>$this->faker->image($path,400,300, 2, false) ,
'originalName' => $pictureName,
'newsId' => $newsId
];
}
}
我在数据库播种机中像这样使用它:
News::factory(3)
->has(Comment::factory()->count(2), 'comments')
->create()
->each(function($news) {
$news->pictures()->save(Picture::factory(null, true)->count(3));
});
但是$galleryId
和$news
不会传递给PictureFactory
。 我哪里做错了? 我该怎么办? 请帮我。
这就是工厂状态的目的。 假设您使用的是当前 (8.x) 版本的 Laravel,请像这样定义您的工厂:
<?php
namespace Database\Factories\App;
use App\Models\{Gallery, News, Picture};
use Illuminate\Database\Eloquent\Factories\Factory;
class PictureFactory extends Factory
{
protected $model = Picture::class;
public function definition()
{
return [
'userId' => 1,
'originalName' => $this->faker->word() . '.jpg',
];
}
public function withGallery($id)
{
$gallery = Gallery::findOrFail($id);
$path = 'public/galleries/' . $gallery->name;
return $this->state([
'src' => $this->faker->image($path, 400, 300, 2, false),
'newsId' => null,
]);
}
public function withNews()
{
$news = News::inRandomOrder()->first();
$path = 'public/newsPicture';
return $this->state([
'src' => $this->faker->image($path, 400, 300, 2, false),
'newsId' => $news->id,
]);
}
}
现在你可以像这样创建你想要的模型:
Picture::factory()->count(3)->withNews();
// or
Picture::factory()->count(3)->withGallery($gallery_id);
我不确定,但我相信你应该能够做到这一点以获得你想要的结果:
Picture::factory()
->count(3)
->withNews()
->for(News::factory()->hasComments(2))
->create();
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