if 和 else 语句 JAVA

Question

我正在练习 if 和 else 语句，我猜测了您的密码字符串，如果您输入了正确的密码，则会出现一条祝贺消息，但如果您输入错误，则会出现另一条消息，上面写着“请再试一次”，我遇到的问题是如果用户再次尝试猜到正确的密码，我不知道如何设置另一条祝贺消息。

public static void main(String[] args) {

    String password = "Shippuden345";
    System.out.println("Enter or guess the password: ");

    Scanner scanner = new Scanner(System.in);
    String guess = scanner.nextLine();

    System.out.println(password.equals(guess));

    if (password.equals(guess)) {
        System.out.println("Your guess was correct");
        return;
    }
    else;
    {
        System.out.println("Please try again: ");
        Scanner scanner1 = new Scanner(System.in);
        String again = scanner1.nextLine();
    }

}

}

我想在这里设置另一条消息，如果用户在重试后猜对了密码。

 else;
    {
        System.out.println("Please try again: ");
        Scanner scanner1 = new Scanner(System.in);
        String again = scanner1.nextLine();
    }

}

}

Answer 1

最好使用 do while 循环：

public static void main(String[] args) {

    String password = "Shippuden345";
    String guess;
    do{
    System.out.println("Enter or guess the password: ");
    guess = scanner.nextLine();

    System.out.println(password.equals(guess));

    if (password.equals(guess)) {
        System.out.println("Your guess was correct");
        return;
    }
    else {
        System.out.println("Please try again: ");
    }

    }while(!password.equals(guess));
}

Answer 2

我已经编辑了你的代码。 但是，我已将其添加到静态无效：

如果第一次尝试不正确，我还添加了一个int以显示。 希望你喜欢。

class s{

public static void check(){

int attempts = 0;

    String password = "Shippuden345";
    System.out.println("Enter or guess the password: ");

    Scanner scanner = new Scanner(System.in);
    String guess = scanner.nextLine();

    System.out.println(password.equals(guess));

while(attempts < 5){
    if (password.equals(guess) && attempts == 0) {
        System.out.println("Your guess was correct");
        return;
    }
else
    if (password.equals(guess) && attempts > 0) {
        System.out.println("Attempt number "+attempts+" was correct.");
        return;
    }

    else{
        System.out.println("Please try again: ");
    attempts++;
guess = scanner.nextLine();
    }
}

}

public static void main(String[] args) {
check();
}

}```

Answer 3

您可以将输入值的输入和处理放在一个无限循环中（例如while(true){} ），您可以在正确的输入上中断。

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        String password = "Shippuden345";
        Scanner scanner = new Scanner(System.in);

        while (true) {
            System.out.print("Enter or guess the password: ");
            String guess = scanner.nextLine();

            if (password.equals(guess)) {
                System.out.println("Your guess was correct");
                break;
            } else {
                System.out.println("Please try again: ");
            }
        }
    }
}

示例运行：

Enter or guess the password: aSD
Please try again: 
Enter or guess the password: 12H
Please try again: 
Enter or guess the password: Shippuden345
Your guess was correct

Answer 4

如果猜测不正确，您可以使用在第一次猜测密码后开始的循环，如果在以下试验中输入的密码不正确，则继续循环。

然后在密码匹配时中断循环并打印祝贺消息。