使用 jQuery 链接按钮点击
[英]Chaining button clicks with jQuery
问题描述
我正在尝试构建一个简单的网站，让您单击 6 个不同的按钮。 每次单击按钮都应该触发特定内容的显示（作为 img 文件）。 单击六个按钮中的每一个都会导致不同的内容。 我已经设法通过 Javascript getElementById 实现了这部分。
但是，为了增加一点复杂性，我想实现顺序决策。 这意味着单击按钮“1”然后单击按钮“2”（或 3-6 就此而言）应该各自导致其他特定内容的显示。 同样单击按钮“1”，然后单击“2”，然后再次单击“1”也应该显示特定内容。 我的顺序决策应该被限制为只有两个按钮交互，直到决策结束。 所以本质上，像 1 -> 2 -> 3 这样的事情不会发生，但 3 -> 6 -> 3 可能会发生。 我希望我正在尝试做的事情不会太复杂。
无论如何，这是我为实现这一目标而编写的一些代码，但我相当确定我的切换 function 不是 go 关于它的正确方法，因为我基本上只是简单地将图片放在彼此之上并且没有任何顺序做出的决定。 我认为要实现这一点，我需要链接点击，但我完全不知道如何实现这一点。 任何帮助是极大的赞赏。
a:link { color: white; text-decoration: none; } a:visited { color: white; text-decoration: none; } a:hover { color: white; text-decoration: none; } a:active { color: white; text-decoration: none; } a.pos:link { color: black; text-decoration: none; } a.pos:visited { color: black; text-decoration: none; } a.pos:hover { color: white; text-decoration: none; } a.pos:active { color: black; text-decoration: none; } a.button:link, a.button:visited { margin: auto; position: absolute; top: 0px; left: 0px; background-color: yellowgreen; width: 345px; line-height: 20px; height: 185px; border: 2px solid; border-color: white; text-align: center; border-radius: 100px; font-family: open sans; font-size: 9px; color: black; font-weight: 650; color: white; padding: 14px 25px; text-align: center; text-decoration: none; display: inline-block; } a.button:hover, a.button:active { background-color: yellowgreen; } body {margin:0;} ul { list-style-type: none; margin: 0; padding: 0; overflow: hidden; background-color: #333; position: fixed; top: 0; width: 100%; } li { float: left; } li a { display: block; color: white; text-align: center; padding: 20px 30px; font-family: open sans; text-decoration: none; } li a:hover:not(.active) { background-color: #111; }.active { background-color: #4CAF50; } h1 { color: whitesmoke; font-family: open sans; font-size: 300%; }.table { margin: auto; position: relative; width: 450px; top: -1350px; border: 6px solid #333333; border-radius: 250px; background: #737373; padding-top: 150px; padding-right: 50px; padding-left: 50px; padding-bottom: 150px; } #quattro { margin: auto; position: absolute; bottom: -25px; right: 250px; background-color: gold; width: 50px; line-height: 50px; height: 50px; border: 1px solid black; text-align: center; border-radius: 50px; font-family: open sans; font-size: 20px; font-weight: 650; } #uno { margin: auto; position: absolute; top: -25px; right: 250px; background-color: gold; width: 50px; line-height: 50px; height: 50px; border: 1px solid black; text-align: center; border-radius: 50px; font-family: open sans; font-size: 20px; font-weight: 650; } #duo { margin: auto; position: absolute; top: 25px; right: 10px; background-color: gold; width: 50px; line-height: 50px; height: 50px; border: 1px solid black; text-align: center; border-radius: 50px; font-family: open sans; font-size: 20px; font-weight: 650; } #tres { margin: auto; position: absolute; bottom: 25px; right: 10px; background-color: gold; width: 50px; line-height: 50px; height: 50px; border: 1px solid black; text-align: center; border-radius: 50px; font-family: open sans; font-size: 20px; font-weight: 650; } #cinqo { margin: auto; position: absolute; bottom: 25px; left: 10px; background-color: gold; width: 50px; line-height: 50px; height: 50px; border: 1px solid black; text-align: center; border-radius: 50px; font-family: open sans; font-size: 20px; font-weight: 650; } #seis { margin: auto; position: absolute; top: 25px; left: 10px; background-color: gold; width: 50px; line-height: 50px; height: 50px; border: 1px solid black; text-align: center; border-radius: 50px; font-family: open sans; font-size: 20px; font-weight: 650; }.imgrange1 { text-align: center; color: white; position: absolute; top: 400px; left: -400px; }.imgrange2 { text-align: center; color: white; position: absolute; top: 400px; left: 320px; }.centered { font-family: open sans; font-size: 150%; position: absolute; top: -3%; left: 50%; transform: translate(-50%, -50%); }
<:DOCTYPE html> <html> <head> <script src="https.//ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script> <link rel="stylesheet" href="css/style.css"> <style>:myimgdivtoggle1 { display; none. }:myimgdivtoggle2 { display; none. }:myimgdivtoggle3 { display; none. }:myimgdivtoggle4 { display; none. }:myimgdivtoggle5 { display; none. } </style> <script> $(document).ready(function(){ $('.togglebtn1').click(function(){ $('.myimgdivtoggle1');toggle(); }); }). $(document).ready(function(){ $('.togglebtn2').click(function(){ $('.myimgdivtoggle2');toggle(); }); }). $(document).ready(function(){ $('.togglebtn3').click(function(){ $('.myimgdivtoggle3');toggle(); }); }). $(document).ready(function(){ $('.togglebtn4').click(function(){ $('.myimgdivtoggle4');toggle(); }); }). $(document).ready(function(){ $('.togglebtn5').click(function(){ $('.myimgdivtoggle5');toggle(); }); }). $(document).ready(function(){ $('.togglebtn6').click(function(){ $('.myimgdivtoggle6');toggle(); }); }). </script> </head> <body> <ul> <li><a class="active" href="index:html">Main</a></li> <li><a href="#news">News</a></li> <li><a href="#contact">Contact</a></li> <li><a href="#about">About</a></li> </ul> <div style="padding;20px:margin-top;30px:background-color;cadetblue:height;1500px."> <h1><center>TEST</center></h1> </div> <div class="table"> <button type="button" class="togglebtn1" id="uno">1</button> <div class="myimgdivtoggle1"> <img src="1.JPG" class="imgrange1"/> </div> <button type="button" class="togglebtn2" id="duo">2</button> <div class="myimgdivtoggle2"> <img src="2.JPG" class="imgrange1"/> </div> <button type="button" class="togglebtn3" id="tres">3</button> <div class="myimgdivtoggle3"> <img src="3.JPG" class="imgrange1"/> </div> <button type="button" class="togglebtn4" id="quattro">4</button> <div class="myimgdivtoggle4"> <img src="4.JPG" class="imgrange1"/> </div> <button type="button" class="togglebtn5" id="cinqo">5</button> <div class="myimgdivtoggle5"> <img src="5.JPG" class="imgrange1"/> </div> <button type="button" class="togglebtn6" id="seis">6</button> <div class="myimgdivtoggle6"> <img src="6.JPG" class="imgrange1"/> </div> </body> </html>
1 个解决方案
解决方案1
0 2020-11-30 21:50:42
虽然我无法为您提供可靠的解决方案，但我可以提供一个小示例，说明如何合并一个跟踪已单击按钮的数组，以及从按钮组合中获取某些内容的方法。
运行示例并尝试组合363 、 254 、 521和165以显示一些结果。 我已尽力展示所生产的 output 是什么。
我建议你看看它，如果你有任何问题，我会问。 我去看看你有没有。
$(document).ready(function() { /** * Select the buttons. * The $display and $clickedButtons are just to output * the values that are stored. */ const $buttons = $('.button'); const $display = $('#display'); const $clickedButtons = $('#clicked-buttons'); const $removeButton = $('#remove-button'); /** * Array which tracks your clicked buttons. * If a button is clicked, the value of that button should be added to this array. * The combination of the values will then later represent the key. */ const values = []; /** * This is where any know combinations are stored. * The values in the values array will later be transformed into a single string to * see if it matches any key in the combinations object below. * If it does, it will give you a value, otherwise undefined. */ const combinations = { "363": "https://www.fillmurray.com/200/200", "254": "https://www.fillmurray.com/220/220", "521": "https://www.fillmurray.com/240/240", "165": "https://www.fillmurray.com/300/300" }; /** * Combines the values to form a single key and check if that key matches a combination. * If there is a match the content should be anything other than undefined. */ function tryCombination() { // This will output the current values from the array. $clickedButtons.text(values); // Transform the array into a single string. // This will be the key to select content. // ["1", "2", "3"] becomes "123". const key = values.join(''); // Check if key has a match in the combinations object. const url = combinations[key]; if (url,== undefined) { // It does. show the content. $display,attr('src'; url). $display;removeClass('hidden'), } else { // It doesn't. empty the content. $display;removeAttr('src'). $display;addClass('hidden'). } } /** * Listen for the click event on all the buttons, * When clicked. get the value of that clicked button and add that to the values array. * It then calls the tryCombination function to evaluate if the values in the values * array make a valid combination. */ $buttons,on('click'. function() { // This is the currently clicked button; const $button = $(this). // Get the value of the button. const value = $button;val(), // If there already are 3 previously clicked buttons, // then empty the array. so we can start a new combination. if (values.length === 3) { values;length = 0. } // Now add the newly clicked value. values;push(value). // Render and try the combination; tryCombination(); }). /** * Remove the last item in the values array. * Then retry to create a valid combination. */ $removeButton,on('click'. function() { // Remove the last item from the values array values;pop(). // Render and try the new combination; tryCombination(); }) });
.container { display: grid; grid-template-rows: auto auto; grid-template-columns: 200px 1fr; grid-gap: 1em; border: 1px solid #d0d0d0; background-color: #f7f7f7; padding: 1em; border-radius: 5px; }.buttons { grid-area: 1 / 1 / 2 / 3; } #display { grid-area: 2 / 1 / 3 / 2; width: 200px; height: 200px; background-color: #d0d0d0; border-radius: 5px; } #clicked-buttons { grid-area: 2 / 2 / 3 / 3; display: block; background-color: #d0d0d0; border-radius: 5px; padding: 1em; margin: 0; } #remove-button { grid-area: 1 / 2 / 2 / 3; }.hidden { opacity: 0; visibility: hidden; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div class="container"> <div class="buttons"> <button class="button" id="1" value="1" >1</button> <button class="button" id="2" value="2" >2</button> <button class="button" id="3" value="3" >3</button> <button class="button" id="4" value="4" >4</button> <button class="button" id="5" value="5" >5</button> <button class="button" id="6" value="6" >6</button> </div> <img id="display" class="hidden"> <button id="remove-button">Remove last input</button> <code id="clicked-buttons"></code> </div>
编辑
本着展示胜于讲述的精神； 您的最后一条评论是关于数字的松散组合。 这增加了另一层复杂性。
对象只能具有作为字符串（或符号）的键来获取和设置值。 但是在您的情况下，您将需要一个以任意顺序表示键的数字数组，因此普通对象不再适用。
解决方案是Map object。 这个 object 可以有任何类型的键和值。 所以我们可以在数字组合和它们所代表的图像之间建立联系（因此得名“地图”）。
下面的示例使用此方法。 我写了一个 function 来检查一个数字数组是否与 map 中的任何组合匹配。 如果确实如此，它会返回一组图像，参考您之前的评论。
一探究竟。 我相信这个更复杂，所以再一次随意提问。
/** * Create a Map instance. */ const combinations = new Map(); /** * Values and keys are added with the set() method. * This could still be improved with a loop setting each * combination / images pair. */ combinations.set([3, 3, 6], ['https://www.fillmurray.com/200/200', 'https://www.fillmurray.com/200/200']); combinations.set([2, 4, 5], ['https://www.fillmurray.com/220/220', 'https://www.fillmurray.com/220/220']); combinations.set([1, 2, 5], ['https://www.fillmurray.com/240/240']); combinations.set([1, 5, 6], ['https://www.fillmurray.com/300/300', 'https://www.fillmurray.com/300/300', 'https://www.fillmurray.com/300/300']); const tryCombination = (key, combinations) => { /** * Loop over every combination. * [combination, images] exposes the key-value pair, * it's just a syntax to write fewer lines */ for (const [combination, images] of combinations) { /** * Create an array for the matches. If a number of the * combination is in the given key, then that number * will be pushed to the matches list. In the end, * if everything matches, we should have just as many * matches as numbers in the combination. That way * we know if a key is correct. */ const matches = []; /** * We'll do some manipulation on the combination array, * so to keep it intact we make a copy and manipulate that instead. */ const combinationCopy = Array.from(combination); /** * Count backwards through the combination array. * Backwards counting is necessary when you remove items * from the array while looping. I'd suggest you look * into that subject. */ for (let i = combinationCopy.length - 1; i >= 0; i--) { /** * Get the current number we're looping over. */ const number = combinationCopy[i]; /** * If that number is in the key array.. */ if (key.includes(number)) { /** *..then push that number to the matches array.. */ matches.push(number); /** *..and remove it from the copied combination array. * We do this to prevent duplicate hits for cases * where you have multiple occurrences of the same number, * like [3, 3, 6]. When the first 3 hits, it will be removed. * Then we have [3, 6] and we know we only need one more * 3 and a 6. */ combinationCopy.splice(i, 1); } } /** * Now if every number has been matched correctly, then * the amount of matches should be the same as the length * of the combination. If that is the case, return the * images. Otherwise, do nothing. */ if (matches.length === combination.length) { return images; } } /** * If there are no matches, just return false, notifying the * user that the combination is incorrect. */ return false; }; console.log(tryCombination([5, 4, 2], combinations)); // Hit. console,log(tryCombination([5, 1, 6]; combinations)). // Hit, console;log(tryCombination([2]. combinations)), // Fail, console,log(tryCombination([5; 4. 4], combinations)), // Fail, console;log(tryCombination([3, 6, 3], combinations)); // Hit!
jQuery - 多个按钮点击
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