从异步 function 中获取返回值而不再次调用它

Question

这是代码：

const onStartRecord = async() => {
  try {
    const path = Platform.select({
      ios: `file:///audio/${filenameGenerator}.m4a`,
      android: `file:///audio/${filenameGenerator}.mp4`,
    });
    const audioSet: AudioSet = {
      AudioEncoderAndroid: AudioEncoderAndroidType.AAC,
      AudioSourceAndroid: AudioSourceAndroidType.MIC,
      AVEncoderAudioQualityKeyIOS: AVEncoderAudioQualityIOSType.high,
      AVNumberOfChannelsKeyIOS: 2,
      AVFormatIDKeyIOS: AVEncodingOption.aac,
    };
    console.log('audioSet', audioSet);
    const uri = await audioRecorderPlayer.startRecorder(path, audioSet);
    audioRecorderPlayer.addRecordBackListener((e: any) => {
      setAudioProp(audioProp => {
        return { ...audioProp,
          recordSecs: e.current_position,
          recordTime: audioRecorderPlayer.mmssss(Math.floor(e.current_position)),
        }
      });

    });

    console.log(`uri: ${uri}`);
    return uri
  } catch (err) {
    console.log(err);
    return;
  }
};

const audioPath = async() => {
  const result = await onStartRecord();
  return result;
}

const onSubmit = async() => {
  const audiopath = await audioPath();
  console.log("this is the audiopath", audiopath)
}
};

当我触发 onSubmit function 时，我可以得到我想要的，但问题是，它还会再次触发 onStartRecord function，这将在我的情况下导致错误，我只想获取 onStartRecord 解决时生成的 uri，但我没有不想再次触发，如果需要使用 onSubmit function 并从 onStartRecord 中获取值怎么办？ 谢谢 ！

Answer 1

而不是返回uri ， onStartRecord应该将其分配给全局变量。

然后audioPath()可以返回该变量。

let savedAudioPath;

const onStartRecord = async() => {
  try {
    const path = Platform.select({
      ios: `file:///audio/${filenameGenerator}.m4a`,
      android: `file:///audio/${filenameGenerator}.mp4`,
    });
    const audioSet: AudioSet = {
      AudioEncoderAndroid: AudioEncoderAndroidType.AAC,
      AudioSourceAndroid: AudioSourceAndroidType.MIC,
      AVEncoderAudioQualityKeyIOS: AVEncoderAudioQualityIOSType.high,
      AVNumberOfChannelsKeyIOS: 2,
      AVFormatIDKeyIOS: AVEncodingOption.aac,
    };
    console.log('audioSet', audioSet);
    const uri = await audioRecorderPlayer.startRecorder(path, audioSet);
    audioRecorderPlayer.addRecordBackListener((e: any) => {
      setAudioProp(audioProp => {
        return { ...audioProp,
          recordSecs: e.current_position,
          recordTime: audioRecorderPlayer.mmssss(Math.floor(e.current_position)),
        }
      });

    });

    console.log(`uri: ${uri}`);
    savedAudioPath = uri;
  } catch (err) {
    console.log(err);
    return;
  }
};

const audioPath = async () => savedAudioPath;