![](/img/trans.png)
[英]Unable to add additional column to an existing table in SpringBoot Hibernate JPA
[英]Springboot Hibernate read data from existing table on SQL Server
我在 SQL 服务器中有一个现有的表。
CREATE TABLE [dbo].[STUDENTS](
[ID] [int] NOT NULL,
[FIRSTNAME] [varchar](50) NOT NULL,
[LASTNAME] [varchar](50) NOT NULL,
[EMAIL] [varchar](100) NOT NULL,
[AGE] [int] NOT NULL,
[ADDRESS] [varchar](3000) NOT NULL,
PRIMARY KEY (ID)
);
我在 JAVA 中创建了这个实体,让我能够使用 Hibernate 提取数据。
package com.My_task_be.spring.model;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name = "STUDENTS")
public class Student {
@Id
@Column(name = "ID")
public int id;
@Column(name = "FISRTNAME")
public String firstName;
@Column(name = "LASTNAME")
public String lastName;
@Column(name = "EMAIL")
public String email;
@Column(name = "AGE")
public int Age;
@Column(name = "ADDRESS")
public String Address;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public int getAge() {
return Age;
}
public void setAge(int age) {
Age = age;
}
public String getAddress() {
return Address;
}
public void setAddress(String address) {
Address = address;
}
}
这是存储库
@Repository
public interface StudentRepository extends CrudRepository<Student, Integer>{
List<Student> findAll();
}
这是 controller
@RestController
public class AppController {
@Autowired
private StudentRepository studentRpository;
@GetMapping("/getAllStudents")
public List<Student> getAllStudents(){
return studentRpository.findAll();
}
@GetMapping("/helloWorld")
public String helloWorld(){
return "Hello World!";
}
}
当我运行http://localhost:8080/getAllStudents
我得到Invalid column name 'fisrtname'.
我不希望 hibernate 创建一个新表,我只想让它从现有表中读取。 而且我已经指定了列名,但它仍然不起作用。
有任何想法吗?
您在 FISRTNAME 中有错字。 它是 FIRSTNAME,更改如下
@Column(name = "FIRSTNAME")
public String firstName;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.