在数组 c# 中添加正负 integer 之和进行循环

Question

“正输入的总和是：”和“负输入的总和是：”部分不起作用没有答案显示可能是什么解决方案？顺便说一句，这是一个 11 年级的问题

int i, num, sum = 0;
Console.Write("\nInput the number of elements to be stored in the array :");
num = Convert.ToInt32(Console.ReadLine());

for (i = 0; i < num; i++)
{
    Console.Write("Elements - {0}:", i, num);
    array[i] = Convert.ToInt32(Console.ReadLine());
}
Console.Write("The positive inputs are :");
for (i = 0; i < num; i++)
{
    if (array[i] >= 0)
    {

        Console.Write(array[i] + ",");
        array[i]++;


    }
}
Console.Write("\nThe sum of positive input is :");
for (i = 0; i < num; i++)
{
    if (array[i] >= 0)
    {
        sum += array[i];
    }
}
    Console.Write("\nThe negative inputs are :");
for (i = 0; i < num; i++)
{
    if (array[i] < 0)
    {
        Console.Write(array[i] + ",");
        array[i]++;

    }
}
Console.Write("\nThe sum of negative input is :");
for (i = 0; i < num; i++)
{
    if (array[i] < 0)
    {
        sum += array[i];
    }
}

Answer 1

特别感谢 Usama 爵士和拖放爵士

int[] array = new int[100];
int i, num, sum = 0;

Console.Write("\nInput the number of elements to be stored in the array :");
num = Convert.ToInt32(Console.ReadLine());

for (i = 0; i < num; i++)
{
    Console.Write("Elements - {0}:", i, num);
    array[i] = Convert.ToInt32(Console.ReadLine());
}

Console.Write("The positive inputs are :");
for (i = 0; i < num; i++)
{
    if (array[i] >= 0)
    {
        Console.Write(array[i] + ",");
    }
}

Console.Write("\nThe sum of positive input is :" );
for (i = 0; i < num; i++)
{
    if (array[i] >= 0)
    {
        sum += array[i];
    }
}

Console.Write(sum);
sum = 0;
Console.Write("\nThe negative inputs are :");
for (i = 0; i < num; i++)
{
    if (array[i] < 0)
    {
        Console.Write(array[i] + ",");
    }
}

Console.Write("\nThe sum of negative input are :" );
for (i = 0; i < num; i++)
{
    if (array[i] < 0)
    {
        sum += array[i];
    }
}

Console.Write(sum);

Answer 2

首先，从用户输入读取数组长度后，您不会初始化数组。 你应该有：

int[] array;
Console.Write("\nInput the number of elements to be stored in the array :");
num = Convert.ToInt32(Console.ReadLine());
array = new int[num];

其次，您对正负计算使用相同的sum变量（中间不重置）。 您可以为这两个计算使用两个单独的变量：

int i, num, posSum = 0, negSum = 0;

第三，正如评论中提到的拖放，你不需要那个array[i]++; ，因为它修改了数组的元素。

第四，正如Usama Aziz在评论中提到的那样，您没有Console.Write打印结果的位置。

最终解决方案应如下所示：

static void Main(string[] args)
{
    int i, num, posSum = 0, negSum = 0;
    int[] array;
    Console.Write("\nInput the number of elements to be stored in the array :");
    num = Convert.ToInt32(Console.ReadLine());
    array = new int[num];

    for (i = 0; i < num; i++)
    {
        Console.Write("Elements - {0}:", i, num);
        array[i] = Convert.ToInt32(Console.ReadLine());
    }

    Console.Write("The positive inputs are :");
    for (i = 0; i < num; i++)
    {
        if (array[i] >= 0)
        {
            Console.Write(array[i] + ",");
        }
    }

    Console.Write("\nThe sum of positive input is :");
    for (i = 0; i < num; i++)
    {
        if (array[i] >= 0)
        {
            posSum += array[i];
        }
    }
    Console.Write(posSum);

    Console.Write("\nThe negative inputs are :");
    for (i = 0; i < num; i++)
    {
        if (array[i] < 0)
        {
            Console.Write(array[i] + ",");
        }
    }

    Console.Write("\nThe sum of negative input is :");
    for (i = 0; i < num; i++)
    {
        if (array[i] < 0)
        {
            negSum += array[i];
        }
    }
    Console.Write(negSum);
}

祝你考试顺利！