ORACLE JSON_TABLE 我需要从数组中获取 2 列

Question

我有这个 SQL 代码

SELECT * FROM JSON_TABLE (('
[
    "tipodenunciaid": [1,2],
    "municipioid": [1,2]
]
'), '$[*]' COLUMNS (tipodenunciaid integer PATH '$.tipodenunciaid[*]', municipioid integer PATH '$.municipioid[*]'));

我想得到下一个结果：

我的查询有什么问题？

太感谢了。

Answer 1

你不能这样使用json_table() 。 如果您希望 arrays 都未嵌套在不同的列中，并根据每个数组中每个元素的 position 排列，那么一个选项是将每个数组单独扩展为行，使用ordinality来跟踪每个元素的 Z4757FE07FD492A8BEEEZA6 然后加入两个结果集。 full join可以方便地容纳每个数组中不相等数量的元素：

with 
    data as (
        select '{ "tipodenunciaid": [1,2,3,4], "municipioid": [1,2,3,4,5] }' as js from dual
    ),
    t as (
        select t.*
        from data d
        cross apply json_table(
            d.js,
            '$.tipodenunciaid[*]' columns (rn for ordinality, tipodenunciaid integer path '$')
        ) t
    ),
    m as (
        select m.*
        from data d
        cross apply json_table(
            d.js,
            '$.municipioid[*]' columns (rn for ordinality, municipioid integer path '$')
        ) m
    )
select t.tipodenunciaid, m.municipioid
from t
full join m on m.rn = t.rn

DB Fiddle 上的演示。

Answer 2

您可以将两个OUTER APPLY与FOR ORDINALITY一起使用来生成数组的纵坐标以将表连接到自身：

SELECT j.id,
       CASE
       WHEN t.id = m.id OR t.id > m.max_id OR m.id IS NULL
       THEN tipodenunciaid
       END AS tipodenunciaid,
       CASE
       WHEN t.id = m.id OR m.id > t.max_id OR t.id IS NULL
       THEN municipioid
       END AS municipioid
FROM   table_name j
       OUTER APPLY (
         SELECT id,
                tipodenunciaid,
                MAX(id) OVER () AS  max_id
         FROM   JSON_TABLE(
                  j.json,
                  '$.tipodenunciaid[*]'
                  COLUMNS (
                    id FOR ORDINALITY,
                    tipodenunciaid integer PATH '$'
                  )
                )
       ) t
       OUTER APPLY (
         SELECT id,
                municipioid,
                MAX(id) OVER () AS  max_id
         FROM   JSON_TABLE(
                  j.json,
                  '$.municipioid[*]'
                  COLUMNS (
                    id FOR ORDINALITY,
                    municipioid integer PATH '$'
                  )
                )
       ) m
WHERE  t.id = m.id
OR     t.id IS NULL
OR     ( m.id > t.max_id AND t.id = t.max_id )
OR     m.id IS NULL
OR     ( t.id > m.max_id AND m.id = m.max_id );

其中，对于样本数据：

CREATE TABLE table_name ( id, json ) AS
SELECT 1, '{"tipodenunciaid":[1,2],"municipioid":[1,2]}' FROM DUAL UNION ALL
SELECT 2, '{"tipodenunciaid":[],"municipioid":[3,4]}' FROM DUAL UNION ALL
SELECT 3, '{"tipodenunciaid":[5],"municipioid":[]}' FROM DUAL UNION ALL
SELECT 4, '{"tipodenunciaid":[6,7],"municipioid":[6]}' FROM DUAL UNION ALL
SELECT 5, '{"tipodenunciaid":[8],"municipioid":[8,9]}' FROM DUAL;

输出：

 身份证 |  TIPODENUNCIAID |  MUNICIPIOID -: |  -------------: |  ----------: 1 |  1 |  1 1 |  2 |  2 2 |  null |  3 2 |  null |  4 3 |  5 |  null 4 |  6 |  6 4 |  7 |  null 5 |  8 |  8 5 |  null |  9

db<> 在这里摆弄