使用对象日期属性对数组进行排序

Question

我有一个包含如下对象的数组：

{
 Title: "Title",
 Url: "myUrl",
 publishedDate: "19/01/2021"
  },
  {
   Title: "Title 2",
Url: "myUrl",
publishedDate: "17/12/2020"
  },
  {
  Title: "Title 3",
Url: "myUrl",
publishedDate: "11/03/2021"
  },
  {
Title: "Title 4",
Url: "myUrl",
publishedDate: "11/12/2020"
  }

我已将它们保存在我的 state（数组）中。

this.state.data

我想根据属性“publishedDate”订购对象（由于 memory 效率，不使用 new Date()）。 我尝试：

console.log(this.state.data.sort(function(a, b) {
  var c = new Date(a.publishedDate);
  var d = new Date(b.publishedDate);
  return c.getTime() - d.getTime();
}))

但是对象不按顺序排列。 代码有什么问题？ 操场：

https://www.typescriptlang.org/play?#code/FAYw9gdgzgLgBAQwE5IQTzgXjgb2HOAEwRgQC44BtPOAFQEsYAbAUwoCIHmX2AafAKpImHALZohTPvgAOAVwBGTelAAWLQgBESbOOwCMATgD0ABn3GATKcv72+OAF9+BGgS6sOHlnEvTJYhLC0vJKKupaOhz6AOzG+pZWNqb2BM4Obt5ejKxwAMz+woGSIYrKahraMLoGFqZ5SbapTi64wFl63nAALIUieuIl-KHlEVU1+hYJjSkOjg4AusDzwKCQUGCsAHRMYADmABTIqGhbxKRbG0gwBwBmchAgMPSQR7xwCgCUbQQAbshwEBYOAQFgAdzg4yOWxG4UqOk+AG4HP8kERgaCIVCFDCynDItUkQ4kCwYHIkBBAVs9qSGKIWAdvgBaIjU2n0emM5GOT6fYBAA

Answer 1

如果日期格式始终相同，您可以创建格式为YYYYMMDD的字符串，然后进行比较 -

 var data = [{ Title: "Title", Url: "myUrl", publishedDate: "19/01/2021" }, { Title: "Title 2", Url: "myUrl", publishedDate: "17/12/2020" }, { Title: "Title 3", Url: "myUrl", publishedDate: "11/03/2021" }, { Title: "Title 4", Url: "myUrl", publishedDate: "11/12/2020" }] var sortedData = data.sort(function(a, b) { a = a.publishedDate.split('/').reverse().join(''); b = b.publishedDate.split('/').reverse().join(''); return a > b? 1: a < b? -1: 0; }); console.log(sortedData);

这里的解决方案也提出了相同的建议（以及使用.localeCompare作为替代方案）

Answer 2

您可以使用 Date.UTC 方法接受年、月索引、日来创建日期并通过解析输入日期字符串来传递这些值，如下所示：

 this.state = { data: [{ Title: "Title", Url: "myUrl", publishedDate: "19/01/2021" }, { Title: "Title 2", Url: "myUrl", publishedDate: "17/12/2020" }, { Title: "Title 3", Url: "myUrl", publishedDate: "11/03/2021" }, { Title: "Title 4", Url: "myUrl", publishedDate: "11/12/2020" }]}; console.log(this.state.data.sort(function(a, b) { var c = Date.UTC(a.publishedDate.split("/")[2], a.publishedDate.split("/")[1] - 1, a.publishedDate.split("/")[0]); var d = Date.UTC(b.publishedDate.split("/")[2], b.publishedDate.split("/")[1] - 1, b.publishedDate.split("/")[0]); return c - d; }))