如果存在单元号，则正则表达式从门牌号开始提取完整地址

Question

如果给定字符串中存在单元号，我正在尝试从门牌号开始提取地址。

如果单元号不可用，则 select 整个字符串。

const adss1 = 'U 4 21 House Ave, Suburb State 2020';

const adss2 = 'U 14 21 House Ave, Suburb State 2020';

const adss3 = '21 House Ave, Suburb State 2020';

const regEx = /(([0-9]+)((\s+[a-zA-Z,]+|\s+[a-zA-Z,.]+\s){2,10})?(\#[0-9a-z-\-]+|\#\s+[0-9\-]+|[0-9\-]+))/g;

const match1 = adss1.match(regEx)
console.log(match1)
// [ '21 House Ave, Suburb State 2020' ]
const match2 = adss2.match(regEx)
console.log(match2)
//[ '14', '21 House Ave, Suburb State 2020' ]
const match3 = adss3.match(regEx)
console.log(match3)
//[ '21 House Ave, Suburb State 2020' ]

当前的正则表达式模式适用于 adss1 和 adss3 地址类型，但不适用于 adss2 变量。

寻找改进我的正则表达式模式的建议。 谢谢

Answer 1

据我所知，一个人只想在开始时跳过所有内容，直到一个匹配空格（序列）之前的第一个数字字符，然后是一个非数字字符； 然后从那里继续匹配所有内容（直到最后）... /\d+\s+\D.*$/ ...

 function extractAddress(data) { return ((/\d+\s+\D.*/).exec(String(data)) || [''])[0]; } console.log([ 'U 4 21 House Ave, Suburb State 2020', 'U 14 21 House Ave, Suburb State 2020', '21 House Ave, Suburb State 2020', 'hasvk 1223 21 House Ave, Suburb State 2020', 'has vk 12 23 21 House Ave, Suburb State 2020', '12 23 21 House Ave, Suburb State 2020', ].map(extractAddress)); console.log(`U 4 21 House Ave, Suburb State 2020 U 14 21 House Ave, Suburb State 2020 21 House Ave, Suburb State 2020 hasvk 1223 21 House Ave, Suburb State 2020 has vk 12 23 21 House Ave, Suburb State 2020 12 23 21 House Ave, Suburb State 2020`.match(/\d+\s+\D.*$/gm));

 .as-console-wrapper { min-height: 100%;important: top; 0; }