堆栈内存溢出
  繁体   English   中英

创建父子关系 JSON 树

[英]Create parent child relation JSON tree

 原文  2020-12-21 16:46:07  8   1    php

问题描述

这是我的代码，我有三个表帖子表、评论表和喜欢表。 我有一个左连接所有三个表的 postid 在所有三个表中都通用。 我正在完美地获取所有数据，但我正在获取重复的 postdata 数据（例如：Postid=1），我不希望这样。 我的问题是获取 Postdata 的重复数据（例如：Postid=1）

<?php
    include "../dcon.php";
    $sql = "select * FROM posts left join comments on comments.Cpostid=posts.PostId left join likes on likes.postid=posts.PostId";


        $query=mysqli_query($mysqli,$sql);  
        $result = mysqli_num_rows($query);
        $menus=array();


     for($i=0; $i<$result; $i++){
    $row = mysqli_fetch_all($query,MYSQLI_ASSOC);
     foreach($row as $index => $row ){
        $menus[]=[
        'PostId'=>$row['PostId'],
        'PostVideo'=>$row['PostVideo'],
        'PostDesc'=>$row['PostDesc'],
        'PostImage'=>$row['PostImage'],
        'PostedBy'=>$row['PostedBy'],
        'UserName'=>$row['UserName'],
        'Status'=>$row['Status'],
        'PostParent'=>$row['PostParent'],
        'likes'=>$row['likes'],
        'comments'=>[
        $index => [
        'commentsid'=>$row['commentsId'],
        'comments'=>$row['comments'],
        'Cpostid'=>$row['Cpostid'],
        'time'=>$row['time'],
        ],],
        
        'likes'=>[
        $index =>[
        'Likeid'=>$row['Lid'],
        'dislikes'=>$row['dislikes'],
        'postid'=>$row['postid'],
        'userid'=>$row['userid'],
]]
];
        }
     }  
     echo json_encode($menus,JSON_PRETTY_PRINT);

?>

我的 output 如下：

[
    {
        "PostId": "1",
        "PostVideo": "v2.mp4",
        "PostDesc": "this is a tutorial on bench press",
        "PostImage": "null",
        "PostedBy": "Irfan khan",
        "UserName": "irfan",
        "Status": "1",
        "PostParent": null,
        "likes": {
            "Likeid": "1",
            "dislikes": "0",
            "postid": "1",
            "userid": "1"
        },
        "comments": {
            "commentsid": "1",
            "comments": "awesome video",
            "Cpostid": "1",
            "time": "2020-12-16 17:33:33"
        }
    },
    {
        "PostId": "1",
        "PostVideo": "v2.mp4",
        "PostDesc": "this is a tutorial on bench press",
        "PostImage": "null",
        "PostedBy": "Irfan khan",
        "UserName": "khan",
        "Status": "1",
        "PostParent": null,
        "likes": {
            "Likeid": "1",
            "dislikes": "0",
            "postid": "1",
            "userid": "1"
        },
        "comments": {
            "commentsid": "2",
            "comments": "good workouts",
            "Cpostid": "1",
            "time": "2020-12-16 17:33:33"
        }
    },
    {
        "PostId": "1",
        "PostVideo": "v1.mp4",
        "PostDesc": "Chicken generally includes low fat in the meat itself (castrated roosters excluded). The fat is highly concentrated on the skin. A 100g serving of baked chicken breast contains 4 grams of fat and 31 grams of protein, compared to 10 grams of fat and 27 grams of protein for the same portion of broiled, lean skirt steak.",
        "PostImage": "im1",
        "PostedBy": "Rehmat",
        "UserName": null,
        "Status": "1",
        "PostParent": null,
        "likes": {
            "Likeid": "20",
            "dislikes": "0",
            "postid": "1",
            "userid": "4"
        },
        "comments": {
            "commentsid": null,
            "comments": null,
            "Cpostid": null,
            "time": null
        }
    },
    {
        "PostId": "1",
        "PostVideo": "v1.mp4",
        "PostDesc": "Chicken generally includes low fat in the meat itself (castrated roosters excluded). The fat is highly concentrated on the skin. A 100g serving of baked chicken breast contains 4 grams of fat and 31 grams of protein, compared to 10 grams of fat and 27 grams of protein for the same portion of broiled, lean skirt steak.",
        "PostImage": "im1",
        "PostedBy": "Rehmat",
        "UserName": null,
        "Status": "1",
        "PostParent": null,
        "likes": {
            "Likeid": "26",
            "dislikes": "0",
            "postid": "1",
            "userid": "4"
        },
        "comments": {
            "commentsid": null,
            "comments": null,
            "Cpostid": null,
            "time": null
        }
    },
    {
        "PostId": "3",
        "PostVideo": null,
        "PostDesc": "this is an image of chicken",
        "PostImage": "post.jpg",
        "PostedBy": "khan",
        "UserName": null,
        "Status": "0",
        "PostParent": null,
        "likes": {
            "Likeid": null,
            "dislikes": null,
            "postid": null,
            "userid": null
        },
        "comments": {
            "commentsid": null,
            "comments": null,
            "Cpostid": null,
            "time": null
        }
    },
    {
        "PostId": "9",
        "PostVideo": null,
        "PostDesc": "gdhgh",
        "PostImage": "ghghdf",
        "PostedBy": null,
        "UserName": null,
        "Status": null,
        "PostParent": null,
        "likes": {
            "Likeid": null,
            "dislikes": null,
            "postid": null,
            "userid": null
        },
        "comments": {
            "commentsid": null,
            "comments": null,
            "Cpostid": null,
            "time": null
        }
    }
];

我想要我的 output 如下所示：

{
            "PostId": "1",
            "PostVideo": "v2.mp4",
            "PostDesc": "this is a tutorial on bench press",
            "PostImage": "null",
            "PostedBy": "Irfan khan",
            "UserName": "irfan",
            "Status": "1",
            "PostParent": null,
            "likes": 
                '0':{
                "Likeid": "1",
                "dislikes": "0",
                "postid": "1",
                "userid": "1"
            }, 
                '1':{
                "Likeid": "1",
                "dislikes": "0",
                "postid": "1",
                "userid": "1"
            }, 
                '2':{
                "Likeid": "1",
                "dislikes": "0",
                "postid": "1",
                "userid": "1"
            }, 
                '3':{
                "Likeid": "1",
                "dislikes": "0",
                "postid": "1",
                "userid": "1"
            },
            "comments": 
               '0':{
                "commentsid": "1",
                "comments": "awesome video",
                "Cpostid": "1",
                "time": "2020-12-16 17:33:33"
            },
               '1':{
                "commentsid": "1",
                "comments": "awesome video",
                "Cpostid": "1",
                "time": "2020-12-16 17:33:33"
            },
               '2':{
                "commentsid": "1",
                "comments": "awesome video",
                "Cpostid": "1",
                "time": "2020-12-16 17:33:33"
            },
               '3':{
                "commentsid": "1",
                "comments": "awesome video",
                "Cpostid": "1",
                "time": "2020-12-16 17:33:33"
            }
        },
 {
            "PostId": "9",
            "PostVideo": null,
            "PostDesc": "gdhgh",
            "PostImage": "ghghdf",
            "PostedBy": null,
            "UserName": null,
            "Status": null,
            "PostParent": null,
            "likes": {
                "Likeid": null,
                "dislikes": null,
                "postid": null,
                "userid": null
            },
            "comments": {
                "commentsid": null,
                "comments": null,
                "Cpostid": null,
                "time": null
            }
        }

1 个解决方案

解决方案1
 0 已采纳  2020-12-21 21:01:02

嗯...起初我认为您的循环是问题所在，而您误解了这种行为。 但是后来我看到了您的“我想要我的 output 如下所示”，这没有任何意义，特别是您想要重复的喜欢/评论。

首先，循环：一个for循环和一个内部foreach循环。 for循环遍历结果的数量。 内部foreach循环遍历所有结果。 因此，如果我们有 6 个结果，而不是仅迭代 6 次，我们迭代 36 次（6 个结果计数 x 6 个结果）。

我们实际上只需要 1 个循环：

$query = mysqli_query($mysqli, $sql);
$menus = [];
$rows = mysqli_fetch_all($query, MYSQLI_ASSOC);
foreach ($rows as $index => $row) {
    $menus[] = [
        ...
    ];
}

接下来，我们通过使用PostId索引$menus来避免重复的帖子。 如果PostId在$menus中还不存在，我们插入帖子； 否则我们只是 append 喜欢/评论：

$query = mysqli_query($mysqli, $sql);
$menus = [];
$rows = mysqli_fetch_all($query, MYSQLI_ASSOC);
foreach ($rows as $row) {
    if (!isset($menus[$row['PostId']])) {
        $menus[$row['PostId']] = [
            'PostId' => $row['PostId'],
            ...
            'comments' => [],
            'likes' => [],
        ];
    }

    $menus[$row['PostId']]['comments'][] = [
        ...
    ];
    $menus[$row['PostId']]['likes'][] = [
        ...
    ];
}

如果由于某种原因您不希望$menus被PostId索引，我们可以在循环之后调用array_values()以使用从零开始的顺序 integer 重新索引它：

foreach (...) { ... }
$menus = array_values($menus);

至于重复的likes / comments ，您对此很明确。 但万一你真的想要不重复，我们也可以通过他们的Likeid和commentsid索引它们，并根据需要插入/忽略：

$query = mysqli_query($mysqli, $sql);
$menus = [];
$rows = mysqli_fetch_all($query, MYSQLI_ASSOC);
foreach ($rows as $row) {
    if (!isset($menus[$row['PostId']])) {
        $menus[$row['PostId']] = [
            'PostId' => $row['PostId'],
            ...
            'comments' => [],
            'likes' => [],
        ];
    }

    if (!isset($menus[$row['PostId']]['comments'][$row['commentsid']])) {
        $menus[$row['PostId']]['comments'][$row['commentsid']] = [
            ...
        ];
    }

    if (!isset($menus[$row['PostId']]['Likes'][$row['Lid']])) {
        $menus[$row['PostId']]['Likes'][$row['Lid']] = [
            ...
        ];
    }
}

如果我们也不希望comments / likes由commentsid / Lid索引，我们也可以在它们上调用array_values() ：

foreach (...) { ... }
$menus = array_values($menus);
foreach ($menus as &$menu) {
    $menu['comments'] = array_values($menu['comments']);
    $menu['likes'] = array_values($menu['likes']);
}
unset($menu);
// Or
array_walk($menus, function (&$menu) {
    $menu['comments'] = array_values($menu['comments']);
    $menu['likes'] = array_values($menu['likes']);
});

暂无
暂无

声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

相关问题 父子关系树是否需要递归函数？ 如何在php中创建父子关系 ElasticSearch 7 &amp; PHP - 为父/子关系创建映射 如何从二叉树表中获取带有父子关系的数据？ 在codeigniter中创建父级及其子级树 如何用PHP和MySQL创建JSON嵌套子父树（PDO方法） 父子关系 PHP 从json数据中获取父子关系中所有子项的总和 从多维无限父子树创建菜单 使用laravel中的数据库创建父子管理菜单树
相关标签
 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM