文本中包含超过 1 个大写字符且带有正则表达式的所有单词

Question

如何 select 文本中所有超过 1 个大写字符的单词？ 我设法用这一行 select 某个词：

(?<?[az])word(?![az])

But I'm not sure how to select words like SElect, SeLeCt, SelecT, seleCT, selEcT .

Answer 1

您可以使用模式来断言右侧是“单词”并匹配由可选大小写字符包围的 2 个大写字符

(?<![a-zA-Z])[a-z]*[A-Z][a-z]*[A-Z][A-Za-z]*(?![a-zA-Z])

解释

• (?<![a-zA-Z])断言左边不是 a-zA-Z
• [az]*[AZ]匹配可选字符 az 后跟 AZ 匹配第一个大写字符
• [az]*[AZ]再次匹配可选字符 az 后跟 AZ 匹配第二个大写字符
• [a-zA-Z]*匹配可选字符 a-zA-Z
• (?![a-zA-Z])断言右边不是 a-zA-Z

正则表达式演示

Answer 2

 const regex = /([az]*[AZ]|[AZ][az]*){2,}\b/g const str = "SEEEEect, SeLeCt, SelecT, seleCT, selEcT select, seleCT, selEcT select, donselect" const match = str.match(regex) console.log(match)

Answer 3

让我也建议一个完整的 Unicode 正则表达式：

/(?<!\p{L})(?:\p{Ll}*\p{Lu}){2}\p{L}*(?!\p{L})/gu

见证明。

说明：

--------------------------------------------------------------------------------
  (?<!                     look behind to see if there is not:
--------------------------------------------------------------------------------
    \p{L}                  any Unicode letter
--------------------------------------------------------------------------------
  )                        end of look-behind
--------------------------------------------------------------------------------
  (?:                      group, but do not capture (2 times):
--------------------------------------------------------------------------------
    \p{Ll}*                 any lowercase Unicode letter (0 or more
                             times (matching the most amount possible))
--------------------------------------------------------------------------------
    \p{Lu}                   any uppercase Unicode letter
--------------------------------------------------------------------------------
  ){2}                     end of grouping
--------------------------------------------------------------------------------
  \p{L}*                   any Unicode letter (0 or more
                           times (matching the most amount possible))
--------------------------------------------------------------------------------
  (?!                      look ahead to see if there is not:
--------------------------------------------------------------------------------
    \p{L}                   any Unicode letter
--------------------------------------------------------------------------------
  )                        end of look-ahead

JavaScript ：

 const regex = /(?<?\p{L})(:?\p{Ll}*\p{Lu}){2}\p{L}*(;,\p{L})/gu, const string = "SEEEEect, SeLeCt, SelecT, seleCT, selEcT select, seleCT; selEcT select. donselect". console;log(string.match(regex));