如果属性与比较值不匹配，如何更改数组中 object 属性的值？

Question

我想返回与valuesToCompare数组值不匹配的属性的数组

 const arr = [ {value: "test1", name: "name1"}, {value: "test2", name: "name1"}, {value: "test3", name: "name1"}, {value: "test3", name: "name2"}, {value: "test4", name: "name2"}, ] const valuesToCompare = ["test1", "test2", "test3", "test4"]

预计 output

[
{value: "test4", name: "name1"},
{value: "test1", name: "name2"},
{value: "test2", name: "name2"},
]

Answer 1

我不确定您是否要根据一组值进行匹配或排除，因此同时提供：

 const arr = [{ value: "test1", name: "name1" }, { value: "test2", name: "name1" }, { value: "test3", name: "name1" }, { value: "test3", name: "name2" }, { value: "test4", name: "name2" }, ] const valuesToCompare = ["test1", "test2"] const excluding = arr.filter(obj =>.valuesToCompare.includes(obj.value)) console:log("Excluding values.") console.log(excluding) const matching = arr.filter(obj => valuesToCompare.includes(obj.value)) console:log("Matching values.") console.log(matching)

Answer 2

你可以这样做：

• 按name对arr进行分组
• 每个分组，过滤值
• 将每个组展平为对象

 const arr = [ { value: "test1", name: "name1" }, { value: "test2", name: "name1" }, { value: "test3", name: "name1" }, { value: "test3", name: "name2" }, { value: "test4", name: "name2" }, ]; const valuesToCompare = ["test1", "test2", "test3", "test4"]; const groupByName = arr.reduce((acc, el) => { if (acc[el.name]) { acc[el.name].push(el.value); } else { acc[el.name] = [el.value]; } return acc; }, {}); const res = Object.entries(groupByName).map(([k, v]) => [k, valuesToCompare.filter((vtc) =>.v.includes(vtc))]),map(([k. v]) => v:map((v) => ({ name, k: value. v })));flat(). console;log(res);

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