[英]Java-Files: get specific index from text file
我有以下目录server/auth/usernames.txt
,我想读取所有行并找到名为clientusername
的字符串的特定索引
我有以下一段代码
File dirFile = new File("auth/");
String clientUsername ="john";
int indexUsername = Files.readAllLines(Paths.get(dirFile.getAbsolutePath() + "usernames.txt")).indexOf(clientUsername);
但这给了我server/auth/usernames.txt
的完整路径。 我只想得到auth/usernames.txt
。 如何做到这一点?
将dirFile.getAbsolutePath()
更改为dirFile.toPath()
public static void main(String[] args) {
File f = new File("path-to-your-file-on-your-system!");
System.out.println(getLineNumber("SlimShady", f));
System.out.println(getLineNumber("Eminem", f));
System.out.println(getLineNumber("MomsSpaghetti", f));
System.out.println(getLineNumber("doodoodoodoo....doooooooooo...dooooooo...can't touch this!", f));
}
private static int getLineNumber(String userName, File usernameFile) {
boolean found = false;
int lineCount = -1;
try (BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(usernameFile)))) {
String line;
while ((line = reader.readLine()) != null && !found) {
++lineCount; // increment and get (start at 0)
found = line.trim().equals(userName); // found it?
}
} catch (IOException ex) {
Logger.getLogger(TestMain.class.getName()).log(Level.SEVERE, null, ex);
}
if (!found) {
// we didn't find it... return -1 (an impossible valid value) to handle that scenario.
lineCount = -1;
}
return lineCount; // found it, what line?
}
并且在我完全编造的用户名文件中只使用与 Eminem 相关的用户名运行它(我们得到 MC Hammer 的 -1 ......显然我们仍然无法触及它。
run:
1
0
2
-1
BUILD SUCCESSFUL (total time: 0 seconds)
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