如何在删除 php 中的产品之前显示弹出消息

Question

     <a href='../../include/Query.php? 
     deletepro=yes&proID=".$row['proID']."&proName=".$row['proName']."' onClick= 'confirmation()'><i 
     class='fas fa-trash-alt' style='color:Gray' ></i></a>

//删除一个产品的数据\ function confirm var r= confirm('you want to delete?') if(r== "true"){ if (isset($_GET['deletepro'])){

         if($_GET['deletepro'] == 'yes'  AND $_GET['proID'] !=''){

    //$sql = "DELETE from main where userid =".$_GET['userid'];
    $sql= "UPDATE products  SET proDeleted=1 where proID= ".$_GET['proID'];
    $query=mysqli_query($con, $sql);
    if ($query) {
        echo "<script> alert('".$_GET['proName']." delete Successfully');
        window.location.href = '../admin/pages/products.php';</script>";
    }


    else{
        echo "error while deleting";
    }
    }
    }
    }
    </script>

然后第一个弹出窗口显示如果用户单击确定然后删除产品。 我不知道如何嵌入或显示弹出消息，所以请有人帮助解决我的问题。 谢谢

Answer 1

可以使用js删除确认如下：

function confirmation() {
    if (!confirm("Do you want to delete")){
       return false;
    }
}