mongoose find查询执行多个条件

Question

我有两个表 vendor 和 vendorOrg 表。 我需要根据 vendorOrg 表标准和类别返回列表

const vendors = [{
  "name" : "Alfred",
  "location" : "FH",
  "vendorOrgId" : "1"
},
{
  "name" : "Alfred",
  "location" : "ADH",
  "vendorOrgId" : "2"
},
{
  "name" : "Alfred",
  "location" : "AFF",
  "vendorOrgId" : "41"
}]

const vendorOrg = [
  {
    "orgName" : "star super market",
    "vendorOrgId" : "1",
    "category" : "grocery",
    "status" : "active"
  },
  {
    "orgName" : "L.f super market",
    "vendorOrgId" : "41",
    "category" : "grocery",
    "status" : "active"
  },
  {
    "orgName" : "Fresh mart",
    "vendorOrgId" : "2",
    "category" : "Milk",
    "status" : "active"
  }
]

下面找条件，1.vendor的表vendorOrgId必须和vendorOrg的表id一样。 2. vendorOrg 表状态应该是活跃的。 如果上述条件成立，我需要一个基于 vendorOrg 表类别的供应商列表类别。

{
    "grocery": [{
            "name": "Alfred",
            "location": "FH",
            "vendorOrgId": "1"
        },
        {
            "name": "Alfred",
            "location": "AFF",
            "vendorOrgId": "41"
        }
    ],
    "milk": [{
        "name": "Alfred",
        "location": "ADH",
        "vendorOrgId": "2"
    }]
}

这可能与 mongoose 相关吗？谢谢！

Answer 1

• $lookup with vendorLog 集合并将vendorOrgId传递给查找管道
• $match所需条件
• $project显示必填字段
• $unwind解构org数组
• $group按org category分组并构建vendors数组
• $group by null 构造key-value格式的数组
• $arrayToObject将键值对数组转换为 object
• $replaceRoot将 object 替换为 root

db.vendors.aggregate([
  {
    $lookup: {
      from: "vendorOrg",
      let: { vendorOrgId: "$vendorOrgId" },
      pipeline: [
        {
          $match: {
            $expr: { $eq: ["$$vendorOrgId", "$vendorOrgId"] },
            status: "active"
          }
        },
        { $project: { _id: 1, category: 1 } }
      ],
      as: "org"
    }
  },
  { $unwind: "$org" },
  {
    $group: {
      _id: "$org.category",
      vendors: {
        $push: {
          name: "$name",
          location: "$location",
          vendorOrgId: "$vendorOrgId"
        }
      }
    }
  },
  {
    $group: {
      _id: null,
      vendors: { $push: { k: "$_id", v: "$vendors" } }
    }
  },
  { $replaceRoot: { newRoot: { $arrayToObject: "$vendors" } } }
])

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