在MySQL中按日期分组来自两个表的总和

Question

我有两个不同的表，lead和click。 我想查询MySQL以获取按日期排序的点击和销售线索所产生的佣金总和。

铅：

id|date      |commission
 1|2009-06-01|400
 2|2009-06-01|300
 3|2009-06-03|350

点击：

id|date      |commission
 1|2009-06-01|1
 2|2009-06-03|2
 3|2009-06-03|1

我想创建一个查询给我（如果可能的话，还会获得未生成潜在客户或点击的日期）：

date      |commission click|commission lead|total commission
2009-06-01|               1|            700|             701
2009-06-02|               0|              0|               0
2009-06-02|               3|            350|             353

（日期实际上是实际数据库中的日期时间。）

我想我必须结合起来：

SELECT count(*) as number_clicks, sum(click.commission) as sum_clicks,
 date(click.time) as click_date from click group by click_date order by click_date

带有：

SELECT count(*)as number_leads, sum(lead.commission) as sum_leads,
 date(lead.time) as lead_date from lead group by lead_date order by lead_date

但是我不能让他们一起工作。

Answer 1

这不会获得带有零的日期，因为您将需要一个日期表或一个存储过程来遍历日期。 一种方法是从联合查询中进行子选择（未经测试）：

SELECT commission_date, SUM(click_commission), SUM(lead_commission), SUM(total_commission)
FROM (SELECT DATE(click.time) AS commission_date, click.commission AS click_commission,
             0 AS lead_commission, click.commission AS total_commission
      FROM click
      UNION ALL
      SELECT DATE(lead.time) AS commission_date, 0 AS click_commission,
             lead.commission AS lead_commission, lead.commission AS total_commission
      FROM lead) AS foo
GROUP BY commission_date
ORDER BY commission_date