![](/img/trans.png)
[英]error TS2345: Argument of type 'OperatorFunction<Object, Object>' is not assignable to parameter of type 'OperatorFunction
[英]error TS2345: Argument of type 'OperatorFunction<User, void>' is not assignable to parameter of type 'OperatorFunction<Object, void>'
我是 Angular 的新手。
我怎么解决这个问题?
我已经安装了Angular CLI: 11.0.7
和Node: 12.18.4
错误:
错误:src/app/_services/account.service.ts:19:7 - 错误 TS2345:“OperatorFunction<User, void>”类型的参数不可分配给“OperatorFunction<Object, void>”类型的参数。 “对象”类型可分配给极少数其他类型。 您的意思是改用“任何”类型吗? “对象”类型缺少“用户”类型的以下属性:用户名、令牌
19 map((response: User) => { ~~~~~~~~~~~~~~~~~~~~~~~~~ 20 const user = response; ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~... 24 } ~~~~~~~~~ 25 }) ~~~~~~~~
account.service.ts
import { HttpClient } from '@angular/common/http';
import { Injectable } from '@angular/core';
import {map} from 'rxjs/operators';
import { User } from '../_models/user';
import { ReplaySubject } from 'rxjs';
export class AccountService {
baseUrl = 'https://localhost:5001/api/';
private currentUserSource = new ReplaySubject<User>(1);
currentUser$ = this.currentUserSource.asObservable();
constructor(private http: HttpClient) { }
login(model: any) {
return this.http.post(this.baseUrl + 'account/login', model).pipe(
map((response: User) => {
const user = response;
if (user) {
localStorage.setItem('user', JSON.stringify(user));
this.currentUserSource.next(user);
}
})
)
}
}
用户.ts
export interface User{
username: string;
token: string;
}
你需要投 http.post return
login(model: any) {
//-------------- here ⇊⇊ ------
return this.http.post<User>(this.baseUrl + 'account/login', model).pipe(
map((user : User) => {
if (user) {
localStorage.setItem('user', JSON.stringify(user));
this.currentUserSource.next(user);
}
})
)
}
http.post 可以转换为用户或任何
也试试
login(model: any){
return this.http.post(this.baseUrl + 'account/login', model).pipe(
map((response: User)=>{
const user = response as User;
if(user){
localStorage.setItem('user', JSON.stringify(user));
this.currentUserSource.next(user);
}
})
)
}
Typescript:类型'字符串| undefined' 不可分配给类型 'string'
"strict": true >>>> "strict": false
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.