有人可以帮我处理这段代码吗，它没有返回我想要的结果

Question

任何人都可以编译这段代码并帮助我，因为它没有返回我想要的结果。 我不知道是返回不起作用还是什么，请帮助我，这是代码：

public class ComputeAverage {
public static void main (String[] args) {

new ComputeAverage().computeAverage(4);
}

 
 public double computeAverage(int how_many)
{ double total_points = 0.0;  // the total of all test scores
  int count = 0;  // the quantity of tests read so far
  while ( count != how_many )
        // at each iteration: total_points == exam_1 + exam_2 + ... + exam_count
        { // ask the user for the next exam score:
          String input = JOptionPane.showInputDialog("Type next exam score:");
          int score = new Integer(input).intValue();
          if (score < 0) {
         JOptionPane.showMessageDialog(null, "Enter a positive numer");
         total_points = total_points - score;
          }
           
          // add it to the total:
          total_points = total_points + score;
          count = count + 1;
          // print a summary of the progress:
          System.out.println("count = " + count + "; total = " + total_points);
         
        }

        // at conclusion: total_points == exam_1 + exam_2 + ... + exam_how_many
   return (total_points / how_many);
 
}
 

 }

Answer 1

您正在将值返回给 main，但您没有在任何地方打印它。 您可以使用挥杆中的警报框来显示结果。

在主 function 代替。，

public static void main (String[] args) {
   new ComputeAverage().computeAverage(4);
}

尝试：

public static void main (String[] args) {
    JOptionPane.showMessageDialog(null,"Exam score : " + new ComputeAverage().computeAverage(4));
}