从表中找到第 n 个不是 null 值

Question

我有如下表，其中包含如下数据

| cust  |   val1  | val2  | val3  | val4  | val5  |
---------------------------------------------------
|  1    |    x1   |       |  x3   |       |       | 
|  2    |         |       |       | x4    |       | 
|  3    |    x1   |       |       |       |       |     
|  4    |    x1   |  x2   |  x3   | x4    |  x5   |

我想要 output 作为

cust val1 val2  val3 val4  val5
1    x1    x3   
2    x4 
3    x1 
4    x1    x2   x3    x4    x5

create table test_nth_nonull (cust varchar2(3),val1 varchar2(3),val2 varchar2(3),val3 varchar2(3), val4 varchar2(3), val5 varchar2(3));
insert into  test_nth_nonull values(1,'x1',null,'x3',null,null);
insert into  test_nth_nonull values(2,null,null,null,'x4',null);
insert into  test_nth_nonull values(3,'x1',null,null,null,null);
insert into  test_nth_nonull values(4,'x1','x2','x3','x4','x5');

select* from test_nth_nonull;

请帮助在查询中实现这一点

Answer 1

您可以使用pivot和unpivot子句。 首先将列反转为行以获取行号（默认情况下该子句忽略空值），然后unpivot “ pivot -down”值回到新位置的行：

with test_nth_nonull (cust,val1,val2,val3,val4,val5) as (
  select 1,'x1',null,'x3',null,null from dual union all
  select 2,null,null,null,'x4',null from dual union all
  select 3,'x1',null,null,null,null from dual union all
  select 4,'x1','x2','x3','x4','x5' from dual
), unpivotted as (
  select *
  from test_nth_nonull
  unpivot (val for col in (val1 as 1, val2 as 2, val3 as 3, val4 as 4, val5 as 5))
), numbered as (
  select u.cust, row_number() over (partition by u.cust order by u.col) as rn, u.val
  from unpivotted u
)
select *
from numbered
pivot (max(val) for rn in (1 as val1, 2 as val2, 3 as val3, 4 as val4, 5 as val5))

Db小提琴在这里。

Answer 2

这是一种选择。

这就是你所拥有的：

SQL> select* from test_nth_nonull order by cust;

CUST   VAL1  VAL2  VAL3  VAL4  VAL5
------ ----- ----- ----- ----- -----
1      x1          x3
2                        x4
3      x1
4      x1    x2    x3    x4    x5

这就是你想要的（阅读代码中的注释）：

SQL> with
  2  temp as
  3    -- concatenate all values
  4    (select cust, val1 ||';'|| val2||';'|| val3||';'|| val4||';'|| val5 val
  5     from test_nth_nonull
  6    ),
  7  temp2 as
  8    -- split concatenated column to rows
  9    (select cust,
 10       regexp_substr(val, '[^;]+', 1, column_value) val,
 11       column_value cv
 12     from temp
 13       cross join table(cast(multiset(select level from dual
 14                                      connect by level <= 5
 15                                     ) as sys.odcinumberlist))
 16    )
 17  -- final result
 18  select cust,
 19    max(case when cv = 1 then val end) v1,
 20    max(case when cv = 2 then val end) v2,
 21    max(case when cv = 3 then val end) v3,
 22    max(case when cv = 4 then val end) v4,
 23    max(case when cv = 5 then val end) v5
 24  from temp2
 25  group by cust
 26  order by cust;

CUST   V1   V2   V3   V4   V5
------ ---- ---- ---- ---- ----
1      x1   x3
2      x4
3      x1
4      x1   x2   x3   x4   x5

SQL>

Answer 3

使用 nvl() 和 decode() 以及 cte 会给你你想要的。 如果 val1 为 null，则 nvl(val1,val2) 将返回 val2，否则将返回 val1。 decode(val2,val1,null,val2) 表示如果 val2 =val1 则 null 否则 val2

with cte as (
select cust , nvl(nvl(nvl(nvl(val1 ,val2) ,val3 ), val4 ), val5 )val1,nvl(nvl(nvl(val2 ,val3 ), val4 ), val5 )val2,nvl(nvl(val3, val4 ), val5 )val3,nvl( val4 , val5 )val4,val5
 from test_nth_nonull
 )
 select cust,val1,decode(val2,val1,null,val2)val2,decode(val3,val2,null,val1,null,val3)val3,decode(val4,val3,null,val2,null,val1,null,val4)val4,decode(val5,val4,null,val3,null,val2,null,val1,null,val5) val5 from cte

Answer 4

我将使用横向连接取消数据透视和 pivot 数据：

select t.*, x.*
from test_nth_nonull t cross join lateral
     (select max(case when seqnum = 1 then val end) as val_1,
             max(case when seqnum = 2 then val end) as val_2,
             max(case when seqnum = 3 then val end) as val_3,
             max(case when seqnum = 4 then val end) as val_4,
             max(case when seqnum = 5 then val end) as val_5
      from (select val, row_number() over (order by n) as seqnum
            from (select 1 as n, t.val1 as val from dual union all
                  select 2, t.val2 as val from dual union all
                  select 3, t.val3 as val from dual union all
                  select 4, t.val4 as val from dual union all
                  select 5, t.val5 as val from dual
                 ) x
            where val is not null
           ) x
     ) x;

与将值放入字符串并处理字符串相比，此版本的优势在于它保留了列的原始数据类型。

在pivot / unpivot上执行此操作的优势应该是性能。 旋转仅在每一行内，应该更快。