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[英]Cannot invoke "com.smart.repository.UserRepository.getUserByUsername(String)" because "this.userRepository" is null
[英]Cannot invoke findByEmail because "this.userRepository" is null error
每次我尝试处理我的 /register 方法时,我一直收到无法调用“com.***.repositories.UserRepository.findByEmail(String)”,因为“this.userRepository”是 null 错误。
我不明白为什么代码会显示为 null。
Controller -
@Controller
@RestController
@RequestMapping("/api/v1")
@CrossOrigin(origins = "*", allowedHeaders = "*")
public class AuthenticationController {
@Autowired
UserService userService;
UserRepository userRepository;
AuthenticationTokenRepository authenticationTokenRepository;
@PostMapping(value = "/register")
public ModelAndView registerUser(ModelAndView modelAndView, User user) {
User existingUser = userRepository.findByEmail(user.getEmail());
if (existingUser != null) {
modelAndView.addObject("message", "This email already exists!");
modelAndView.setViewName("error");
} else {
userRepository.save(user);
AuthenticationToken authenticationToken = new AuthenticationToken(user);
authenticationTokenRepository.save(authenticationToken);
SimpleMailMessage mailMessage = new SimpleMailMessage();
mailMessage.setTo(user.getEmail());
mailMessage.setSubject("Complete Registration!");
mailMessage.setFrom("***@gmail.com");
mailMessage.setText("To confirm your account, please click here : "
+ "http://localhost:8080/confirm-account?token=" + authenticationToken.getConfirmationToken());
emailSenderService.sendEmail(mailMessage);
modelAndView.addObject("email", user.getEmail());
modelAndView.setViewName("successfulRegisteration");
}
return modelAndView;
}
}
Axios 调用 -
submit() {
let formData = new FormData();
formData.set("firstName" , this.firstName)
formData.set("lastName", this.lastName)
formData.set("email", this.email)
formData.set("password", this.password)
formData.set("captchaToken", this.captchaToken)
formData.set("agreedToTermsOfService", true)
axios.post("http://localhost:8080/api/v1/register", formData,
{headers: {'Content-Type': 'application/json'}})
.then(res => {
if (res.status === 200) {
this.$router.push('/register-complete');
} else {
console.log(res.data.code);
}
})
.catch(function (err) {
console.log(err);
})
}
我的用户存储库 -
@Repository
public interface UserRepository extends JpaRepository<User, Long> {
User findByEmail(String email);
}
只需将@Autowired 添加到您希望通过 spring 自动装配的相关字段。
更改您的代码
@Autowired
UserService userService;
UserRepository userRepository;
AuthenticationTokenRepository authenticationTokenRepository;
至
@Autowired
UserService userService;
@Autowired
UserRepository userRepository;
@Autowired
AuthenticationTokenRepository authenticationTokenRepository;
我有两个解决方案。
从字段中消除@Autowired; 用构造函数参数替换它们(如果你只有一个构造函数,Spring 会自动理解这些,不需要 @Autowired 注释)。
在您的“配置类”例如(安全配置)中使用@Autowired 创建字段注入,并使用参数化构造函数创建目标 class object 并传递注入的字段。
尝试将以下属性添加到您的 application.properties 文件中。
spring.jpa.properties.javax.persistence.validation.mode=none
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