[英]REGEX - Match a pattern in a lengthy string
我正在尝试匹配长字符串中的特定模式:
NEW ZEALAND AND (data.operator1:"SHELL AND AMP" AND data.field:"NEW ZEALAND") OR (data.operator: purpose AND data.field:crank) OR (data.operator:REGULATOR AND data.field:HELICOPTOR )
基本上是 /(?<?AND)(?<?OR)\s+(:!AND)(?!OR)/g 和 :" [a-zA-Z ] " 的组合
我想将字符串更改为标题大小写,以便我可以清楚地区分 AND/OR/NOT。
新西兰 AND (data.operator1:"Shell And Amp" AND data.field:"New Zealand") OR (data.operator: purpose AND data.field:crank) OR (data.operator:Regulator AND data.field:Helicoptor )
您可以使用带有命名组的正则表达式轻松表达词法分析器,例如:
const MY_LEXER = String.raw`
(?<string> "[^"]*")
|
(?<operator> and|or|AND|OR)
|
(?<word> \w+)
|
(?<punct> [().:])
|
(?<ws> \s+)
`
下一个 function 获取一个字符串和一个词法分析器并返回一个对列表[token-type, token-value]
:
let tokenize = (str, lexer) =>
[...
str.matchAll(
lexer.replace(/\s+/g, ''))
]
.flatMap(m =>
Object
.entries(m.groups)
.filter(p => p[1]))
结果会像
[ 'word', 'NEW' ],
[ 'ws', ' ' ],
[ 'word', 'ZEALAND' ],
[ 'ws', ' ' ],
[ 'operator', 'AND' ],
[ 'ws', ' ' ],
[ 'punct', '(' ],
等等。现在应该可以迭代它,根据需要转换值并将它们重新组合在一起:
for (let [type, val] of tokenize(myString, MY_LEXER)) {
if (type === 'string' || type === 'word')
val = val.toLowerCase();
output += val;
}
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