要求用户重复该程序

Question

如果用户选择 Y，我试图让程序重复，但如果用户选择 N，程序将显示课程的总费用。 我在这里使用 do...while 循环，我不知道为什么，当用户键入 Y 时，程序没有重复以及如何显示总费用。 这是我的编码，还没有完成

#include<stdio.h>
#define A 100
#define B 100
#define C 120
#define D 120
#define E 130

int main()
{
    int totalFee;
    char code, join;
    
    printf("\t\t Training Centre\n");

    do
    {
        printf("\nEnter course code: ");
        scanf(" %c", &code);
        
            if(code == 'A')
            {
                printf("Course name: C for beginner\nFees: 100");
            }
        
            else if(code == 'B')
            {
                printf("Course name: C++ for beginner\nFees: 110");
            }
            
            else if(code == 'C')
            {
                printf("Course name: Java for beginner\nFees: 120");
            }
        
            else if(code == 'D')
            {
                printf("Course name: Phyton for beginner\nD\nFees: 130");
            }
        
            else
            {
                printf("Course name: PHP for beginner\nFees: 140");
            }
    
        printf("\n\nDo you want to join other class? (Enter Y for 'Yes' / N for 'N'): ");
        scanf(" %c", join);
    }
    
    while (join == 'Y' || join == 'y');
    
}

Answer 1

您忘记了scanf(" %c", join)中的地址运算符& ； a sensible compiler with appropriate options would have warned about that.