[英]Count case expression with wildcards
假设我有这个查询:
SELECT
(CASE
WHEN troublequeue LIKE '%DL%' THEN 'Distribution Line Crew'
WHEN troublequeue LIKE '%MS%' THEN 'Service Crew'
WHEN troublequeue LIKE '%TM%' THEN 'Troubleman'
WHEN troublequeue LIKE '%TT%' THEN 'Tree Crew'
WHEN troublequeue LIKE '%POLE%' THEN 'Pole Job'
WHEN troublequeue LIKE '%XFMR%' THEN 'Xfmr Job'
WHEN troublequeue LIKE '%TOC%' THEN 'Tennesee One Call'
ELSE 'Other' END) as HeldJobType,
COUNT(eventid)
FROM
electric_jobs
WHERE
BeginDateTime BETWEEN TO_DATE('<{[begin_date]}>', 'MM/DD/YYYY') AND TO_DATE('<{[end_date]}>', 'MM/DD/YYYY')
AND troublequeue IS NOT NULL
GROUP BY
(CASE
WHEN troublequeue LIKE '%DL%' THEN 'Distribution Line Crew'
WHEN troublequeue LIKE '%MS%' THEN 'Service Crew'
WHEN troublequeue LIKE '%TM%' THEN 'Troubleman'
WHEN troublequeue LIKE '%TT%' THEN 'Tree Crew'
WHEN troublequeue LIKE '%POLE%' THEN 'Pole Job'
WHEN troublequeue LIKE '%XFMR%' THEN 'Xfmr Job'
WHEN troublequeue LIKE '%TOC%' THEN 'Tennesee One Call'
ELSE 'Other' END)
ORDER BY
(CASE
WHEN troublequeue LIKE '%DL%' THEN 'Distribution Line Crew'
WHEN troublequeue LIKE '%MS%' THEN 'Service Crew'
WHEN troublequeue LIKE '%TM%' THEN 'Troubleman'
WHEN troublequeue LIKE '%TT%' THEN 'Tree Crew'
WHEN troublequeue LIKE '%POLE%' THEN 'Pole Job'
WHEN troublequeue LIKE '%XFMR%' THEN 'Xfmr Job'
WHEN troublequeue LIKE '%TOC%' THEN 'Tennesee One Call'
ELSE 'Other' END)
但是当我运行查询时,所有具有多个输入的字段都会作为 DL 返回。 即使一个字段中有多个输入,我如何才能让 SQL 每次发生其中一个时给我一个计数? 当有一个带有逗号和多个输入的字段时,问题就出现了。
样本数据示例是
Troublequeue <- column name
1 TM
2 DL
3 DL
4 DL
5 AMI/STPR
6 PM
7 PM,CR
8 DL
9 TM
10 AMI/STPR
11 TM
12 AMI/STPR
13 AMI/STPR
14 PM
15 AMI/STPR
16 PM
17 MS
18 TOCY, TCN, TT, DL, POLE
如果我理解正确,你想要count(distinct)
:
count(distinct troublequeue)
这将返回每行的不同值的数量。
您可能还想要:
min(troublequeue), max(troublequeue)
获取值的示例。
请注意,许多数据库允许您使用:
group by HeldJobType
所有数据库都应允许:
order by HeldJobType;
您可以使用:
WITH trouble_ids ( id, HeldJobType ) AS (
SELECT 'DL', 'Distribution Line Crew' FROM DUAL UNION ALL
SELECT 'MS', 'Service Crew' FROM DUAL UNION ALL
SELECT 'TM', 'Troubleman' FROM DUAL UNION ALL
SELECT 'TT', 'Tree Crew' FROM DUAL UNION ALL
SELECT 'POLE', 'Pole Job' FROM DUAL UNION ALL
SELECT 'XFMR', 'Xfmr Job' FROM DUAL UNION ALL
SELECT 'TOC', 'Tennesee One Call' FROM DUAL
),
job_ids ( event_id, troublequeue, job_id, lvl, max_lvl ) AS (
SELECT event_id,
troublequeue,
REGEXP_SUBSTR( troublequeue, '[A-Z]+', 1, 1, 'i' ),
1,
REGEXP_COUNT( troublequeue, '[A-Z]+', 1, 'i' )
FROM electric_jobs
WHERE BeginDateTime BETWEEN DATE '2021-01-01' AND DATE '2021-02-01'
UNION ALL
SELECT event_id,
troublequeue,
REGEXP_SUBSTR( troublequeue, '[A-Z]+', 1, lvl + 1, 'i' ),
lvl + 1,
max_lvl
FROM job_ids
WHERE lvl < max_lvl
)
SELECT COALESCE( t.HeldJobType, 'Other' ) AS HeldJobType,
COUNT( e.event_id )
FROM job_ids e
LEFT OUTER JOIN trouble_ids t
ON ( e.job_id = t.id )
GROUP BY
COALESCE( t.HeldJobType, 'Other' );
其中,对于您的示例数据:
CREATE TABLE electric_jobs ( event_id, troublequeue ) AS
SELECT 1, 'TM' FROM DUAL UNION ALL
SELECT 2, 'DL' FROM DUAL UNION ALL
SELECT 3, 'DL' FROM DUAL UNION ALL
SELECT 4, 'DL' FROM DUAL UNION ALL
SELECT 5, 'AMI/STPR' FROM DUAL UNION ALL
SELECT 6, 'PM' FROM DUAL UNION ALL
SELECT 7, 'PM,CR' FROM DUAL UNION ALL
SELECT 8, 'DL' FROM DUAL UNION ALL
SELECT 9, 'TM' FROM DUAL UNION ALL
SELECT 10, 'AMI/STPR' FROM DUAL UNION ALL
SELECT 11, 'TM' FROM DUAL UNION ALL
SELECT 12, 'AMI/STPR' FROM DUAL UNION ALL
SELECT 13, 'AMI/STPR' FROM DUAL UNION ALL
SELECT 14, 'PM' FROM DUAL UNION ALL
SELECT 15, 'AMI/STPR' FROM DUAL UNION ALL
SELECT 16, 'PM' FROM DUAL UNION ALL
SELECT 17, 'MS' FROM DUAL UNION ALL
SELECT 18, 'TOCY, TCN, TT, DL, POLE' FROM DUAL;
输出:
手持式 | 计数(E.EVENT_ID):---------- | ----------------: 配电线船员 | 5 极工作 | 1 其他 | 17 树队 | 1 服务人员 | 1 麻烦人 | 3
db<> 在这里摆弄
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