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[英]Writing elements to a file as they are dequeued from the queue : Scala fs2 Stream
[英]fs2 Stream from queue doesn't consume elements
我想从将所有元素打印到控制台的队列中创建 stream。 当前的一个片段不打印任何内容:
object TestApp extends App {
implicit val contextShift: ContextShift[IO] = IO.contextShift(ExecutionContext.global)
private val value: IO[(fs2.Stream[IO, Unit], String => IO[Unit], () => IO[Unit])] = for {
queue <- Queue.noneTerminated[IO, String]
} yield {
val stream: fs2.Stream[IO, Unit] = queue.dequeue.map(println)
def send(msg: String): IO[Unit] = queue.enqueue1(Some(msg))
def close(): IO[Unit] = queue.enqueue1(None)
(stream, send _, close _)
}
val (stream, send, close) = value.unsafeRunSync()
send("msg1").unsafeRunSync()
send("msg2").unsafeRunSync()
}
stream 创建有什么问题?
在您的示例中,您只是创建了一个队列并创建了 stream 的描述。 为了运行 stream,您需要调用compile
这将公开几个方法,这将允许运行和使用 steam 的值,例如toList
、 fold
或drain
在您的情况下,您对值并不真正感兴趣,因为您只想打印它们,所以您应该使用drain
:
implicit val contextShift: ContextShift[IO] = IO.contextShift(ExecutionContext.global)
implicit val timer: Timer[IO] = IO.timer(ExecutionContext.global)
private val value: IO[(fs2.Stream[IO, Unit], String => IO[Unit], () => IO[Unit])] = for {
queue <- Queue.noneTerminated[IO, String]
} yield {
//I changed map to evalMap, since printing is effect and should be wrapped in IO
val stream: fs2.Stream[IO, Unit] = queue.dequeue.evalMap(v => IO(println(v)))
def send(msg: String): IO[Unit] = queue.enqueue1(Some(msg))
def close(): IO[Unit] = queue.enqueue1(None)
(stream, send _, close _)
}
val (stream, send, close) = value.unsafeRunSync()
send("msg1").unsafeRunSync()
send("msg2").unsafeRunSync()
//Closing of stream will be delayed by 5s and run in separate fiber
close().delayBy(5.seconds).start.unsafeRunSync()
//steam would block here until it's closed
stream.compile.drain.unsafeRunSync()
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