从同一个 class 中的另一个私有方法访问变量 - 这可能吗？

Question

我得到指示创建一个返回 Int“inputAge”的方法，条件是来自方法“run”的先前输入变量“age”大于 18。

但是，由于 Int“age”是在“run”方法中声明和定义的，我无法在从“inputAge”返回 int 的方法中访问它，因此我无法检查 Int“age”是否大于 18。

指令 state 我必须在此代码中使用“inputAge”方法，因此在“run”方法中不检查输入变量“age”是否大于 18。

这些说明是从我分配的工作表中逐字提取的（请原谅任何英语不好的老师）：

"在代理示例中添加以下功能。年龄需要大于或等于 18。如果年龄小于 18，程序会再次询问，直到输入大于等于 18 的数字。你应该实现一个方法名为 inputAge 并从运行中调用该方法。方法如下（已添加在计算机实验室可用的 Java 文件中）"

public int inputAge()
{
        // add the code here to receive an integer number as input and 
        // check if the number is greater or equal to 18
        // if the number is less than 18, the program should ask the number again
        // until the input number is greater or equal to 18
        return(0);//note that 0 was added here just to be able to compile
}

import java.util.*;

public class AgencyInterface 
{ 
    private void run() 
    {
       Scanner console = new Scanner(System.in);
       Couple c = new Couple();
       int      age,end;
       String   name;
       
       do {
           System.out.print("first person: "); 
           System.out.print("name: "); 
           name = console.next();
           System.out.print("age: "); 
           age = console.nextInt();
           c.addData(1,name,age);

           System.out.print("second person: "); 
           System.out.print("name: "); 
           name = console.next();
           System.out.print("age: "); 
           age = console.nextInt();
           c.addData(2,name,age);

           System.out.println("********************");
           System.out.println(c.test());           
           System.out.println("********************");
           System.out.print("Quit? (0)yes (1)no: "); 
           end = console.nextInt();
           }
       while (end!=0);
    }
    public static void main(String[] args)
    {
           AgencyInterface agency = new AgencyInterface ();
           agency.run();
    }
    public int inputAge()
    {
            // add the code here to receive an integer number as input and 
            // check if the number is greater or equal to 18
            // if the number is less than 18, the program should ask the number again
            // until the input number is greater or equal to 18

                // The four comments above give instruction again what to do within here.
                // They were not written by me (Lachshmock).
            return(0);//note that 0 was added here just to be able to compile

    }

    }

Answer 1

看起来您需要替换出现的两个行：

System.out.print("age: "); 
age = console.nextInt();

和

age = inputAge();

然后inputAge应该是这样的：

public int inputAge()
{
    int age;
    do {
        // Get the age from stdin. Print error if < 18
    } while (age < 18);
    return age;
}

我遗漏了一些东西，因为这看起来像家庭作业。