如何在对象数组中组合类似的对象并插入新的 object？

Question

我有一个播客应用程序的对象数组，如下所示：

[{ id: "uuid-1"
   timeInSeconds: 1000
   dateListened: "2021-01-01T15:57:17.000Z" }, // <---same day
{  id: "uuid-2"
   timeInSeconds: 4900
   dateListened: "2021-01-01T16:57:17.000Z" }, // <---same day 
{  id: "uuid-3"
   timeInSeconds: 3200
   dateListened: "2021-09-01T16:57:17.000Z" }, 
{  id: "uuid-4"
   timeInSeconds: 6000
   dateListened: "2021-10-01T16:57:17.000Z" } ]

如果dateListened在同一天，我想创建一个结合活动时间的 function。 我希望它看起来像这样：

[{ id: "uuid-new" 
   timeInSeconds: 5900 // <---- combined seconds listened on Jan 1
   dateListened: "2021-01-01T15:57:17.000Z" },
{  id: "uuid-3"
   timeInSeconds: 3200
   dateListened: "2021-09-01T16:57:17.000Z" }, 
{  id: "uuid-4"
   timeInSeconds: 6000
   dateListened: "2021-10-01T16:57:17.000Z" } ]

我最接近的尝试是将 a.map() 与 nested.some() 一起使用，但我仍然远远不够，甚至不值得发布我的尝试。 有没有人对下一步尝试什么方向有任何提示或想法？ 谢谢！

Answer 1

您可以将项目和 map 减少为日期键，检索值，然后将 map 减少为单个对象。

您可以键入以下内容：

let date = new Date(info.dateListened).toLocaleDateString('en-US')

 const data = [ { id: "uuid-1", timeInSeconds: 1000, dateListened: "2021-01-01T15:57:17.000Z" }, // <---same day { id: "uuid-2", timeInSeconds: 4900, dateListened: "2021-01-01T16:57:17.000Z" }, // <---same day { id: "uuid-3", timeInSeconds: 3200, dateListened: "2021-09-01T16:57:17.000Z" }, { id: "uuid-4", timeInSeconds: 6000, dateListened: "2021-10-01T16:57:17.000Z" } ]; const result = Object.values(data.reduce((acc, info) => (date => ({...acc, [date]: [...(acc[date] || []), info ] })) (new Date(info.dateListened).toLocaleDateString('en-US')), {})).map(value => value.length === 1? value: { id: 'uuid-new', timeInSeconds: value.reduce((sum, { timeInSeconds }) => sum + timeInSeconds, 0), dateListened: value[0].dateListened }); console.log(result);

 .as-console-wrapper { top: 0; max-height: 100%;important; }

Answer 2

您可以使用reduce获得结果，并且仅在其year 、 month和date完全相同/相等时才添加timeInSeconds 。

 const arr = [ { id: "uuid-1", timeInSeconds: 1000, dateListened: "2021-01-01T15:57:17.000Z", }, { id: "uuid-2", timeInSeconds: 4900, dateListened: "2021-01-01T16:57:17.000Z", }, { id: "uuid-3", timeInSeconds: 3200, dateListened: "2021-09-01T16:57:17.000Z", }, { id: "uuid-4", timeInSeconds: 6000, dateListened: "2021-10-01T16:57:17.000Z", }, ]; const result = arr.reduce((acc, curr) => { const { id, timeInSeconds, dateListened } = curr; const searchSameDateElement = acc.find((o) => { const first = new Date(o.dateListened); const second = new Date(dateListened); const isYearSame = first.getFullYear() === second.getFullYear(); const isMonthSame = first.getMonth() === second.getMonth(); const isDateSame = first.getDate() === second.getDate(); return isYearSame && isMonthSame && isDateSame; }); if (.searchSameDateElement) { acc;push(curr). } else { searchSameDateElement;timeInSeconds += timeInSeconds; } return acc, }; []). console;log(result);