从子节点ID中查找子节点的父节点？

Question

我有一个 object 数组，其中有多个子节点，如何从子 object id 中找到父 object。

 [
  {
    id: "a1",
    name: "apple",
    subGroups: [
      {
        id: "a2",
        name: "apple-a",
        subGroups: [
          {
            id: "a3",
            name: "apple-b",
            subGroups: [
              {
                id: "a4",
                name: "apple-c",
                subGroups: [
                  {
                    id: "a5",
                    name: "apple-d",
                    subGroups: [
                      
                    ]
                  }
                ]
              }
            ]
          }
        ]
      }
    ]
  },
  {
    id: "b2",
    name: "orange",
    subGroups: [
      {
        id: "b2",
        name: "orange-a",
        subGroups: [
          {
            id: "b3",
            name: "orange-b",
            subGroups: [
              {
                id: "b4",
                name: "orange-c",
                subGroups: [
                  {
                    id: "b5",
                    name: "orange-d",
                    subGroups: [
                      
                    ]
                  }
                ]
              }
            ]
          }
        ]
      }
    ]
  }
];

如果id = a4 ，则 output 应该是：

 [
  {
    id: "a1",
    name: "apple",
    subGroups: [
      {
        id: "a2",
        name: "apple-a",
        subGroups: [
          {
            id: "a3",
            name: "apple-b",
            subGroups: [
              {
                id: "a4",
                name: "apple-c",
                subGroups: [
                  {
                    id: "a5",
                    name: "apple-d",
                    subGroups: [
                      
                    ]
                  }
                ]
              }
            ]
          }
        ]
      }
    ]
  }
]

如果id = b3 ， output 应该是：

 [
 {
    id: "b2",
    name: "orange",
    subGroups: [
      {
        id: "b2",
        name: "orange-a",
        subGroups: [
          {
            id: "b3",
            name: "orange-b",
            subGroups: [
              {
                id: "b4",
                name: "orange-c",
                subGroups: [
                  {
                    id: "b5",
                    name: "orange-d",
                    subGroups: [
                      
                    ]
                  }
                ]
              }
            ]
          }
        ]
      }
    ]
  }
]

我试过了：

const find = (array, id) => (Array.isArray(array) ? 
            array : [array]).flatMap(o => o.id=== id? o : find(o.subGroups, id)), data = group, result = find(data, event.id);

Answer 1

您可以通过 3 个步骤完成：

1. 像这样使用递归技术来确定每个孩子的parentID 。

[
  {"id": "a1","parentId": "a1"},
  {"id": "a2","parentId": "a1"},
  ...
  {"id": "b2", "parentId": "b2"},
  {"id": "b3", "parentId": "b2"}
  ...
]

2. 像这样通过childID准确获取parentId

const parentId = child_parent_Mapping.find(r => r.id === childID)?.parentId;

3. 按parentId过滤来自arr的结果。

 let arr = [{ id: "a1", name: "apple", subGroups: [{id: "a2", name: "apple-a", subGroups: [{id: "a3", name: "apple-b", subGroups: [{id: "a4", name: "apple-c", subGroups: [{id: "a5", name: "apple-d", subGroups:[]}]}]}]}]}, { id: "b2", name: "orange", subGroups: [{id: "b2", name: "orange-a", subGroups: [{id: "b3", name: "orange-b", subGroups: [{id: "b4", name: "orange-c", subGroups: [{id: "b5", name: "orange-d", subGroups:[]}]}]}]}]}]; // Step 1 const flatItems = (arr, parentId = "") => { return arr.flatMap(({id, subGroups}) => { const childrens = flatItems(subGroups, parentId || id); return [{id, parentId: parentId || id}, ...childrens]; }); }; const child_parent_Mapping = flatItems(arr); const filter_arr = (childID) => { // Step 2 const parentId = child_parent_Mapping.find(r => r.id === childID)?.parentId; // Step 3 return arr.filter(r => r.id === parentId); } console.log({Child: "a1", output: filter_arr('a1')}); console.log({Child: "a4", output: filter_arr('a4')}); console.log({Child: "b3", output: filter_arr('b3')});

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Answer 2

我不知道这到底是不是想要的，但是从下面的代码中，您可以找到每个child id的最后一个父母的最终手段：

 const arr = [{ id: "a1", name: "apple", subGroups: [{id: "a2", name: "apple-a", subGroups: [{id: "a3", name: "apple-b", subGroups: [{id: "a4", name: "apple-c", subGroups: [{id: "a5", name: "apple-d", subGroups:[]}]}]}]}]}, { id: "b2", name: "orange", subGroups: [{id: "b2", name: "orange-a", subGroups: [{id: "b3", name: "orange-b", subGroups: [{id: "b4", name: "orange-c", subGroups: [{id: "b5", name: "orange-d", subGroups:[]}]}]}]}]}]; const res = []; const id = "a4"; arr.map(obj=>{ const str = JSON.stringify(obj); if(str.search(id)>-1){ res.push(obj); } }) console.log(res); //result array