从嵌套的对象数组中获取总和

Question

我有以下对象数组。 如您所见，每个对象中都有一个名为count的嵌套 object。 我想获得Closed 、 Verify和Analyze的总数

例如， Closed的总数为 23， Verify为 3， Analyze为 20

"byPerson": [
      {
        "personId": "973567318",
        "firstName": "Others",
        "lastName": "",
        "count": {
          "Closed": 7,
          "Verify": 3,
          "Analyze": 19
        }
      },
      {
        "personId": "1514903899",
        "firstName": "Yatish",
        "lastName": "Patel",
        "count": {
          "Closed": 16,
          "Analyze": 1
        }
      }
 ]

我尝试过这种方式，但没有奏效。 例如，获得Closed的总数

cosnt result = data.reduce((a, b) => ({"Closed": a.count["Closed"] + b.count["Closed"]}));

Answer 1

 const byPerson = [ { "personId": "973567318", "firstName": "Others", "lastName": "", "count": { "Closed": 7, "Verify": 3, "Analyze": 19 } }, { "personId": "1514903899", "firstName": "Yatish", "lastName": "Patel", "count": { "Closed": 16, "Analyze": 1 } } ]; const sum = byPerson.reduce((agg, item) => { ['Closed', 'Verify', 'Analyze'].forEach(f => agg[f] += item.count[f] || 0); return agg; }, {Closed: 0, Verify: 0, Analyze: 0}); console.log(sum);

Answer 2

将数据减少到 object 中，其中包含您想要总计的嵌套属性的键。 在 reduce 回调中，解构“totals”属性和嵌套的count属性并计算总和。

 const data = [ { "personId": "973567318", "firstName": "Others", "lastName": "", "count": { "Closed": 7, "Verify": 3, "Analyze": 19 } }, { "personId": "1514903899", "firstName": "Yatish", "lastName": "Patel", "count": { "Closed": 16, "Analyze": 1 } } ]; const totalCount = data.reduce(({ Closed, Analyze, Verify }, { count }) => ({ Closed: Closed + (count?.Closed || 0), Analyze: Analyze + (count?.Analyze || 0), Verify: Verify + (count?.Verify || 0), }), { Closed: 0, Analyze: 0, Verify: 0, }); console.log(totalCount);

Answer 3

在这种情况下，您甚至不需要 reduce 并且可以使用简单的循环以及迭代Object.keys()

 const byPerson = [ { "personId": "973567318", "firstName": "Others", "lastName": "", "count": { "Closed": 7, "Verify": 3, "Analyze": 19 } }, { "personId": "1514903899", "firstName": "Yatish", "lastName": "Patel", "count": { "Closed": 16, "Analyze": 1 } } ]; const sum = {Closed: 0, Verify: 0, Analyze: 0} byPerson.forEach(({count})=> { Object.keys(sum).forEach(k => sum[k] += (count[k] || 0)) }); console.log(sum);