遍历 ul li 元素并获取不包括 children 的 li 文本

Question

您好，我如何遍历 ul li 元素并仅从 li 获取文本内容，除了其子项的文本内容？

<li class="lom">@paul<div class="on-off">offline</div></li>
<li class="lom">@alex<div class="on-off">offline</div></li>
<li class="lom">@jhon<div class="on-off">offline</div></li>

我只想得到@paul而没有离线，我试过这个：

var lnx = $('.cht(ul class) .lom');
for (let i = 0; i < lnx.length; i++) {
    var txt = lnx[i].textContent;
    console.log(txt + '\n');
}

但我得到@pauloffline

Answer 1

遍历.childNodes ，按 nodeType 为 3（文本节点）过滤，以仅获取文本节点子节点的节点：

 const texts = [...document.querySelector('.lom').childNodes].filter(node => node.nodeType === 3).map(node => node.textContent).join(''); console.log(texts);

 <ul> <li class="lom">@paul<div class="on-off">offline</div></li> </ul>

Answer 2

这是一个使用.ignore() 微插件的 jQuery 变体

 $.fn.ignore = function(sel) { return this.clone().find(sel||">*").remove().end(); }; // Get LI element by text const $userLI = (text) => $(".lom").filter((i, el) => $(el).ignore().text().trim() === text); // Use like $userLI("@paul").css({color: "gold"});

 <ul> <li class="lom">@paul <span class="on-off">offline</span></li> <li class="lom">@alex <span class="on-off">offline</span></li> <li class="lom">@jhon <span class="on-off">offline</span></li> <li class="lom">@paul</li> </ul> <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>

Answer 3

Jquery解决方案使用replace

https://developer.mozilla.org/fr/docs/Web/JavaScript/Reference/Global_Objects/String/replace

 $('.lom').each(function(index, value) { var getContent = $(this).text(); var replaceTxt = getContent.replace('<div class="on-off">offline</div>','').replace('offline',''); //$(this).find('.on-off').remove(); if (replaceTxt == '@paul') { console.log(replaceTxt); } });

 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <li class="lom">@paul<div class="on-off">offline</div></li> <li class="lom">@alex<div class="on-off">offline</div></li> <li class="lom">@jhon<div class="on-off">offline</div></li>