如何从 oracle sql 的单行中的多列中获取不同的值

Question

我有一排这样的数据

id  first_cd    sec_cd  third_cd    fourth_cd   fifth_cd     sixth_cd
1   A           B           null        C           C            D
                    

output 应该是：

id  first_cd    sec_cd  third_cd    fourth_cd   fifth_cd     sixth_cd
1   A           B       C           D           D               D

我需要从列中获取不同的值并删除存在的空值。

如果， first_cd...sixth_cd 是同一行上的列。 1 AB null C C D are the values Anyway to do in this in oracle sql

Answer 1

这是使用横向连接的好地方：

select t.*, x.*
from t cross join lateral
      (select max(case when seqnum = 1 then cd end) as cd1,
              max(case when seqnum = 2 then cd end) as cd2,
              max(case when seqnum = 3 then cd end) as cd3,
              max(case when seqnum = 4 then cd end) as cd4,
              max(case when seqnum = 5 then cd end) as cd5,
              max(case when seqnum = 6 then cd end) as cd6             
      from (select t.*, row_number() over (order by n) as seqnum
            from (select t.cd1 as cd, 1 as n from dual union all
                  select t.cd2, 2 from dual union all
                  select t.cd3, 3 from dual union all
                  select t.cd4, 4 from dual union all
                  select t.cd5, 5 from dual union all
                  select t.cd6, 6 from dual 
                 ) x
            where cd is not null
           ) x
      ) x;

注意：这会将多余的值返回为NULL ，这似乎更符合您的问题。