[英]converting Excel array formula to VBA code
大家好
我在 excel 中有这个数组公式,我想将它合并到 VBA 代码中,但它给了我一个错误,即无法设置 Range ZA2F2ED4F8EBC2CBB4C21A290DC40AB61DZ 的FormulaArray
属性(错误 100DC40AB61DZ)
这是我在代码中修改后的公式
"=IF(SUMPRODUCT(--(($D$2=$B9)*(E$7>=$D$3)*(E$7<=$D$4)*(NOT(E$6>=1))*(NOT(E$8='الجمعة'))))=1;VLOOKUP($D$5;LeavesTypes;2;0);"""")"
这是完整的代码
Option Explicit
Option Base 1
Dim wrk As Workbook, DataSH As Worksheet, CurrentSH As Worksheet
Dim FirstCol As Integer, EmpRow As Integer, EmpID As String
Dim GetEmpRowLoop As Integer, StartingEmpCol As Integer
Dim StartColLoop As Integer, EndingEmpCol As Integer
Dim EndColLoop As Integer
Public Sub Macro1()
Set wrk = ThisWorkbook
Set DataSH = wrk.Worksheets("الاجازات ")
Set CurrentSH = wrk.ActiveSheet
If CurrentSH.Name = DataSH.Name Then
MsgBox "Please Navigate to an Active Sheet", vbCritical
Exit Sub
End If
EmpID = CurrentSH.Range("d2").Value
For GetEmpRowLoop = 9 To CurrentSH.Cells(Cells.Rows.Count, 2).End(xlUp).Row
If CurrentSH.Cells(GetEmpRowLoop, 2).Value = EmpID Then
EmpRow = GetEmpRowLoop
Exit For
End If
Next GetEmpRowLoop
For StartColLoop = 4 To CurrentSH.Cells(EmpRow, Cells.Columns.Count).End(xlToRight).Column
If CurrentSH.Cells(7, StartColLoop).Value = CurrentSH.Range("D3").Value Then
StartingEmpCol = StartColLoop
Exit For
End If
Next StartColLoop
For EndColLoop = 4 To CurrentSH.Cells(EmpRow, Cells.Columns.Count).End(xlToRight).Column
If CurrentSH.Cells(7, EndColLoop).Value = CurrentSH.Range("D4").Value Then
EndingEmpCol = EndColLoop
Exit For
End If
Next EndColLoop
CurrentSH.Range(Cells(EmpRow, StartingEmpCol), Cells(EmpRow, StartingEmpCol)).FormulaArray = _
"=IF(SUMPRODUCT(--(($D$2=$B9)*(E$7>=$D$3)*(E$7<=$D$4)*(NOT(E$6>=1))*(NOT(E$8='الجمعة'))))=1;VLOOKUP($D$5;LeavesTypes;2;0);"""")"
End Sub
我试图放置公式本身或结果是否无关紧要。
您需要将单引号 (') 替换为双引号 ("")。 但是,您需要将引号加倍...
(NOT(E$8=""الجمعة""))
顺便说一句,不需要SUMPRODUCT
。 以下应该足够了...
.Formula = "=IF(($D$2=$B9)*(E$7>=$D$3)*(E$7<=$D$4)*(NOT(E$6>=1))*(NOT(E$8=""الجمعة""))=1;VLOOKUP($D$5;LeavesTypes;2;0);"""")"
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.