给定一个嵌套的 object 我需要读取值并在数组中显示 output

Question

输入 -

{
    name: 'hi',
    rollNo: {
        id: 3,
        sub: {
            type: ['math','science']
        }
    }
    }

输出["hi",3,"math","science"]

我写的代码

var flattenObject = function(obj){
      for(var i in obj){
        if(!obj.hasOwnProperty(i))continue;
        if(typeof obj[i] === "object" && !Array.isArray(obj[i]) && obj[i] !== null){
        flattenObject(obj[i]);
        }
        if(Array.isArray(obj[i]) && obj[i] !== null){
          
           //handling array condition
        }
        result.push(obj[i]);
        
      }
      console.log("Array",result);
      return result;
    }

对此有任何线索，或者可能有其他方法可以解决？

Answer 1

您可以使用递归flatMap 。

 const o = { name: 'hi', rollNo: { id: 3, sub: { type: ['math', 'science'] } } }; const getEntries = (o, f) => { const obj = f? o[1]: o; return obj === Object(obj)? Object.entries(obj).flatMap(e => getEntries(e, true)): [o]; } console.log(getEntries(o));

Answer 2

You can try with Object.values , witch return values for all enumerable props, if specific value is object (works also for arrays but not nulls) you can recursively call the function. 如果你想跳过 nulls/undefined 添加一些if和continue 。

function values(obj) {
    var v = Object.values(obj);
    var out = [];
    for (let i = 0; i < v.length; i++) {
        const element = v[i];
        if (element !== null && typeof element === 'object') {
            out = out.concat(values(element));
            continue;
        }
        out.push(element);
    }

    return out;
}

输入：

var xx = {
    name: 'hi',
    rollNo: {
        id: 3,
        sub: {
            type: ['math', 'science']
        },
        undef: undefined,
        nil: null,
        fal: false,
        ze: 0
    }
};

output：

[ 'hi', 3, 'math', 'science', undefined, null, false, 0 ]