如何在没有脚本部分的情况下将 package.json 复制到 dist 文件夹

Question

I'm using webpack to bundle my javascript library and I'm currently copying the package.json to the dist folder using CopyWebpackPlugin .

(...)
plugins: [
        new CopyPlugin({
            patterns: [{
                from: "package.json",
                to: "dist"
            }],
        })
    ],
(...)

我想知道是否可以在没有脚本标签的情况下复制package.json ：

{
    "name": "monaco-javascript-compiler",
    "version": (...),
    "description": "(...)",
    "main": (...),
    "scripts": {
        "test": "echo \"Error: no test specified\" && exit 1",
        "debug": "npx webpack --config webpack.config.js --mode=development",
        "build": "npx webpack --config webpack.config.js --mode=production"
    },
    "repository": {
        "type": "git",
        "url": "git+https://github.com/RicardoGomesRocha/monaco-javascript-compiler.git"
    },
    "author": "Ricardo Rocha",
    "dependencies": {(...)},
    "devDependencies": {(...)}
}

I know a solution that involves using gulp to read the package.json , remove the script tag from the JSON and output a new file with that JSON, but I'm trying to avoid that.

Answer 1

CopyWebpackPlugin中有一个名为transform的选项，它允许您在将文件复制到 dist 文件夹之前修改文件的内容。

在此处查看文档： CopyWebpackPlugin