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[英]How to clone rust library, change it and then use it in my own project
[英]How to use a clone in a Rust thread
在这个 rust 程序中,在运行 function 中,我试图将“pair_clone”作为两个线程的参数传递,但我一直收到不匹配的类型错误? 我以为我正在传递这对,但它说我正在传递一个 integer 代替。
use std::sync::{Arc, Mutex, Condvar};
fn producer(pair: &(Mutex<bool>, Condvar), num_of_loops: u32) {
let (mutex, cv) = pair;
//prints "producing"
}
}
fn consumer(pair: &(Mutex<bool>, Condvar), num_of_loops: u32) {
let (mutex, cv) = pair;
//prints "consuming"
}
}
pub fn run() {
println!("Main::Begin");
let num_of_loops = 5;
let num_of_threads = 4;
let mut array_of_threads = vec!();
let pair = Arc ::new((Mutex::new(true), Condvar::new()));
for pair in 0..num_of_threads {
let pair_clone = pair.clone();
array_of_threads.push(std::thread::spawn( move || producer(&pair_clone, num_of_loops)));
array_of_threads.push(std::thread::spawn( move || consumer(&pair_clone, num_of_loops)));
}
for i in array_of_threads {
i.join().unwrap();
}
println!("Main::End");
}
你有两个主要错误
第一个:您使用对的名称作为循环索引。 这使得pair
成为编译器抱怨的 integer。
第二个:您使用一个副本,而您需要两个副本,一个用于生产者,另一个用于消费者
编辑后
use std::sync::{Arc, Mutex, Condvar};
fn producer(pair: &(Mutex<bool>, Condvar), num_of_loops: u32) {
let (mutex, cv) = pair;
//prints "producing"
}
fn consumer(pair: &(Mutex<bool>, Condvar), num_of_loops: u32) {
let (mutex, cv) = pair;
//prints "consuming"
}
pub fn run() {
println!("Main::Begin");
let num_of_loops = 5;
let num_of_threads = 4;
let mut array_of_threads = vec![];
let pair = Arc ::new((Mutex::new(true), Condvar::new()));
for _ in 0..num_of_threads {
let pair_clone1 = pair.clone();
let pair_clone2 = pair.clone();
array_of_threads.push(std::thread::spawn( move || producer(&pair_clone1, num_of_loops)));
array_of_threads.push(std::thread::spawn( move || consumer(&pair_clone2, num_of_loops)));
}
for i in array_of_threads {
i.join().unwrap();
}
println!("Main::End");
}
请注意,我没有对代码质量给予任何关注。 刚刚修复了编译错误。
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