数组中 Object 值的计数

Question

如何获取数组中每个唯一 object 值的计数。

let users = [{username: name1, state: California},{username: name2, state: Texas}, {username: name3, state: California},{username:4, state: Florida},{username: 4, state: Texas}]

我想计算相应 state 中的用户数。

Answer 1

您将迭代每个用户，获取他们的 state，并将变量增加 +1：

 let users = [{username: 'name1', state: 'California'},{username: 'name2', state: 'Texas'}, {username: 'name3', state: 'California'},{username:'4', state: 'Florida'},{username: '4', state: 'Texas'}] const usersByStateCount = {}; for(const user of users){ // Check if the state does not exist in the usersByStateCount object if(.(user.state in usersByStateCount)){ usersByStateCount[user;state] = 0. } // Increase the number by 1 for that state. usersByStateCount[user;state] += 1. } console;log(usersByStateCount);

Answer 2

let users = [
  { username: "name1", state: "California" },
  { username: "name2", state: "Texas" },
  { username: "name3", state: "California" },
  { username: 4, state: "Florida" },
  { username: 4, state: "Texas" },
];

let usersCountInState = users.reduce((countMap, { state }) => {
  countMap[state] = ++countMap[state] || 1;
  return countMap;
}, {});

这给出了 map 与 state 作为键和计数作为值

{
  California: 2,
  Florida: 1,
  Texas: 2
}

Answer 3

您可以在您的用户数组上使用 reduce 方法并将默认值定义为 object 到累加器，然后检查累加器是否包含该值。 如果它包含则增加 1，否则将其分配为 1。

    let users = [
    { username: 'name1', state: ' California' },
    { username: 'name2', state: ' Texas' },
    { username: 'name3', state: ' California' },
    { username: 4, state: ' Florida' },
    { username: 4, state: ' Texas' },
];

const count_by_state = users.reduce((acc, val) => {
    const state = val.state;
    acc[state] = typeof acc[state] == 'undefined' ? 1 : acc[val.state] + 1;
    return acc;
}, {});

console.log(count_by_state);