如何组合 2 个相同的 SQL 查询

Question

您能帮我组合来自同一个表的 2 个类似的 select sql 查询，如下所示：

查询 #1

SELECT COUNT(name) 
FROM orders 
WHERE name = '$product_name' 
  AND order_status LIKE '%returned%'

查询 #2：

SELECT COUNT(name) 
FROM orders 
WHERE name = '$name_ru' 
  AND order_status LIKE '%returned%'

我试图用“OR”运算符将“name='$product_name'”和“name='$name_ru'”分开，但这向我展示了两个结果，我什至尝试了 UNION ALL 但没有运气，有人可以告诉我完成我的任务的正确方法？

Answer 1

如果在 excel 中，您可以显示所需的 output，那么很容易回答。 根据我的理解，您希望结果并排。 请根据您的表更改表名和列名。

    SELECT SUM(ISNULL(Counter1,0)) Counter1,SUM(ISNULL(Counter2,0)) Counter2 from 
(
SELECT CASE WHEN [NAME] LIKE '%a%' THEN COUNT(1) END Counter1,
CASE WHEN [NAME] LIKE '%af%' THEN COUNT(1) END Counter2 
from EMP
GROUP BY Name
)A

Answer 2

$sql="SELECT
  COUNT(name) filter (WHERE name = '$product_name' AND order_status LIKE '%returned%') AS nb1,
  COUNT(name) filter (WHERE name = '$name_ru' AND order_status LIKE '%returned%') AS nb2
  FROM orders";

在 postgresql 上工作

和“不太优雅”，但可以在 postgresl、mysql、...

SELECT nb1,nb2 FROM 
  ( SELECT 1 AS id,COUNT(name) AS nb1
FROM orders 
WHERE name = '$product_name' AND order_status LIKE '%returned%'
) r1
  JOIN
  ( SELECT 1 AS id,COUNT(name) AS nb2
FROM orders 
WHERE name = '$name_ru' AND order_status LIKE '%returned%'
) r2 USING (id);

这个也可以工作（在 postgresql 上可以，要在 mysql 上测试）

SELECT nb1,nb2 FROM 
  ( SELECT COUNT(name) AS nb1
FROM orders 
WHERE name = '$product_name' AND order_status LIKE '%returned%'
) r1
  JOIN
  ( SELECT COUNT(name) AS nb2
FROM orders 
WHERE name = '$name_ru' AND order_status LIKE '%returned%'
) r2 ON true;

Answer 3

尝试这个。

SELECT COUNT(CASE WHEN name = '$product_name' and order_status LIKE '%returned%' then 1 else NULL end),
       COUNT(CASE WHEN name = '$name_ru' AND order_status LIKE '%returned%' then 1 else null end)
FROM orders o

Answer 4

其他人的类似方法，但它们都与整个订单表背道而驰。 通过执行 count(case) AND 应用 where 子句，您可以限制要测试的数据量并简化 case 子句。

SELECT 
      SUM(CASE WHEN name = '$product_name' then 1 else 0 end ) Name1Count,
      SUM(CASE WHEN name = '$name_ru' then 1 else 0 end) Name2Count
   FROM 
      orders o
   where
          -- only consider those with a "%returned%" qualifier
          order_status LIKE '%returned%' 
      -- AND also the two name values you are looking for
      AND name in ('$product_name', '$name_ru' )

Answer 5

谢谢大家的回答，但正如我所见，没有一种简单而优雅的方式来组合这两个查询，所以我决定将它们分开，然后像下面这样一个接一个地获取，它完成了这项工作，但不是很漂亮我期望的方式：

$query_returned = "SELECT COUNT(name) FROM orders WHERE name='$product_name' AND order_status LIKE '%returned%'";
$data_returned = mysqli_query($conn,$query_returned) 或 die("错误：".mysqli_error($conn)); $show_data_returned = mysqli_fetch_array($data_returned);

                $data_returned_cnt = $show_data_returned['COUNT(name)'];
      
                $query_returned_ru = "SELECT COUNT(name) FROM orders WHERE name='$name_ru' AND order_status LIKE '%returned%'";  
                $data_returned_ru = mysqli_query($conn,$query_returned_ru) or die("Error : ".mysqli_error($conn));
                $show_data_returned_ru = mysqli_fetch_array($data_returned_ru);
                
                $data_returned_cnt_ru = $show_data_returned_ru['COUNT(name)'];

回声（$data_returned_cnt + $data_returned_cnt_ru）；