从对象数组中的嵌套数组中删除重复项

Question

我有这个对象数组：

const arrayOfObjects = [{
    id: 10,
    children: [1000]
  },
  {
    id: 10,
    children: [2000]
  },
  {
    id: 20,
    children: [1000]
  },
  {
    id: 20,
    children: [1000, 2000]
  },
  {
    id: 20,
    children: [2000]
  },
];

我想使用以下代码删除重复项：

  const arrayHashMap = arrayOfObjects.reduce((obj, item) => {
    if (obj[item.id]) {
      // obj[item.id].children.push(...item.children);
      const temporaryArray = [...obj[item.id].children, ...item.children];
      obj[item.id].children = [...new Set(temporaryArray)];
    } else {
      obj[item.id] = {
        ...item
      };
    }
    return obj;
  }, {});
  const result = Object.values(arrayHashMap);

在这段代码中，我注释了将值推送到数组的部分。 我尝试使用“new Set”从最终数组中删除重复项，但我总是将值分配给“obj[item.id].children”。 这可以吗还是有更好的方法来写这个？

预期结果：

[{
  id: 10,
  children: [1000, 2000]
}, {
  id: 20,
  children: [1000, 2000]
}]

谢谢

Answer 1

如果值不存在，您可以按id分组并检查数组，然后推送该值。

 const data = [{ id: 10, children: [1000] }, { id: 10, children: [2000] }, { id: 20, children: [1000] }, { id: 20, children: [1000, 2000] }, { id: 20, children: [2000] }], result = Object.values(data.reduce((r, { id, children }) => { r[id]??= { id, children: [] }; children.forEach(v => { if (.r[id].children.includes(v)) r[id].children;push(v); }) return r, }; {})). console;log(result);

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Answer 2

我不知道“更好”，但也许更简洁：

 const arrayOfObjects = [{ id: 10, children: [1000] }, { id: 10, children: [2000] }, { id: 20, children: [1000] }, { id: 20, children: [1000, 2000] }, { id: 20, children: [2000] }, ]; const arrayHashmap = arrayOfObjects.reduce((obj, { id, children }) => ({...obj, [id]: { id, children: [...new Set([...obj[id]?.children?? [], ...children ])] } }), {}) const result = Object.values(arrayHashmap); console.log(result)

编辑：哎呀，“整洁”按钮改变了语义。 固定的。

Answer 3

使用Array#prototype#reduce减少数组并在 children 属性上初始化一个集合，并继续添加到集合中，最后将 map 集合回数组。

 const arrayOfObjects = [{ id: 10, children: [1000] }, { id: 10, children: [2000] }, { id: 20, children: [1000] }, { id: 20, children: [1000, 2000] }, { id: 20, children: [2000] }, ]; const result = Object.values( arrayOfObjects.reduce((r, c) => { r[c.id] = r[c.id] || { id: c.id, children: new Set() }; c.children.forEach((item) => r[c.id].children.add(item)); return r; }, Object.create(null)) ).map((x) => ({ id: x.id, children: [...x.children] })); console.log(result);

Answer 4

 const arr = [ { id: 10, children: [1000], }, { id: 10, children: [2000], }, { id: 20, children: [1000], }, { id: 20, children: [1000, 2000], }, { id: 20, children: [2000], }, ]; let result = arr.reduce((acc, i) => { let obj = acc.find((a) => a.id === i.id); obj? (obj.children = [...new Set(obj.children.concat(i.children))]): acc.push(i); return acc; }, []); console.log(result);

Answer 5

你可以试试这个小提琴： https://jsfiddle.net/d0kboywv/2/

const arrayOfObjects = [
  {
    id: 10,
    children: [1000]
  },
  {
    id: 10,
    children: [2000]
  },
  {
    id: 20,
    children: [1000]
  },
  {
    id: 20,
    children: [1000, 2000, 3000]
  },
  {
    id: 20,
    children: [2000, 4000]
  },
];

let mappedArray = new Map(arrayOfObjects.map(o => [o.id, {}] ));
for (let obj of arrayOfObjects) {
    let child = mappedArray.get(obj.id);
    for (let [key, val] of Object.entries(obj.children)) {
        child[key] = (child[key] || new Set).add(val);
    }
}
let result = Array.from(mappedArray.entries(), ([id, child]) => ({ 
    id, 
    children: [...new Set(Object.entries(child).map(([k, v]) => 
        [...v]
    ).reduce((a, b) => a.concat(b), []))].sort()
}));
console.log(result);

它为我完成了这项工作！

Answer 6

您可以临时将数据结构转换为更简单

常量 objectOfArray = {}; 你的身份是关键，你的孩子是价值

我使用名称 initialData 来引用您的数组

  const objectOfArray = {};
  initialData.forEach(e => {
    if (objectOfArray[e.id] {
      objectOfArray[e.id].push(...e.children);
    } else {
      objectOfArray[e.id] = [...e.children];
    }
  });


  const result = Object.entries(objectOfArray).map(([id, children]) => {
    return {
      id,
      children: children.filter((e, i) => i === chilren.indexOf(i)),
    }
  });

Answer 7

您还可以通过运行以下代码来实现预期的 output

makeMapping = {};
for (let obj of arrayOfObjects) {
    makeMapping[obj.id] = {...obj, children: [...new Set([...obj.children, ...(makeMapping[obj.id]?.children || [])])]};
}
console.log(Object.values(makeMapping));