[英]await Async function with selenium Nodejs
当您使用 selenium 在 Google 上搜索某些内容时,我正在创建一个小程序来返回所有链接标题的名称
这是代码:
const {Builder,By, Key, until} = require('selenium-webdriver');
driver = new Builder().forBrowser("firefox").build();
var search_query='tigers';
(async()=>{
await driver.get(`https://www.google.com/search?q=${search_query}`);
await driver.findElements(By.css('h3')).then((search_results)=>{
for (var i = 0; i < search_results.length; i++)
search_results[i].getText().then((text)=>{console.log(text);})
});
console.log('...Task Complete!')
})();
当你运行它时,output 如下:-
...Task Complete. Tiger - Wikipedia Top stories Tigers (2014 film) - Wikipedia Detroit Tigers (@tigers) · Twitter Tiger | Species | WWF Videos Official Detroit Tigers Website | MLB:com Tiger | WWF Tiger - National Geographic Kids Tiger guide, species facts. how they hunt and where to see in... Related searches Images Description
显然...Task Complete!
应在整个 function 完成后记录
我不明白我做错了什么我使用了适当的await
关键字来保持代码流有序, then()
中的错误是什么?
由于您的.then(()=>...)
不返回 Promise,因此开头的await
关键字什么也不做。 Node 已经启动了获取 h3、获取其文本内容并记录它们的 Promise,但是您放错位置的await
并没有告诉 Node 等待所有这些完成。 您需要await
获取元素,然后同步循环遍历所有元素, await
文本,然后同步打印文本,最后同步打印"...Task Complete!"
const { Builder, By, Key, until } = require('selenium-webdriver');
const driver = new Builder().forBrowser("firefox").build();
const search_query = 'tigers';
(async () => {
await driver.get(`https://www.google.com/search?q=${search_query}`);
const h3Elements = await driver.findElements(By.css('h3'));
for (const h3 of h3Elements) {
const text = await h3.getText();
console.log(text);
}
console.log('...Task Complete!')
})();
如果你想减少额外的变量,你可以这样做:
const { Builder, By, Key, until } = require('selenium-webdriver');
const driver = new Builder().forBrowser("firefox").build();
const search_query = 'tigers';
(async () => {
await driver.get(`https://www.google.com/search?q=${search_query}`);
const h3Elements = await driver.findElements(By.css('h3'));
for (const h3 of h3Elements) {
console.log(await h3.getText());
}
console.log('...Task Complete!')
})();
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