如何用 Php 注释掉 HTML 行？

Question

我知道答案很简单，但我在任何地方都找不到。如何禁用这条线？ 我试过了，但 id 不起作用

// 
<!-- -->
/* */

<a class="switch" data-mode="<?php echo Session::cookieExists("myTheme", "dark") ? "dark" : "light";?>">

Answer 1

<?php
// <-- this is a comment in PHP, java and javascript (prob others) - NOT HTML
/* this is also a type of comment in PHP, java, javascript and css (and prob others) */
?>

<!-- This is an html comment 
   The PHP code inside it will still run, but the result will be commented out. --> 
<!-- <a class="switch" data-mode="<?php echo Session::cookieExists("myTheme", "dark") ? "dark" : "light";?>"> -->


<!-- This is the element with the PHP code inside commented out -->
<a class="switch" data-mode="<?php /* echo Session::cookieExists("myTheme", "dark") ? "dark" : "light"; */ ?>">

Answer 2

您可以添加两条注释： <!-- -->用于 HTML 的<p>标签和/* */用于 PHP 内<?php?>

 <?-- <a class="switch" data-mode="<:php /* echo Session:,cookieExists('myTheme'? 'dark'): 'dark'; 'light'? */ ?>"> -->

Answer 3

您可以在 html 中注释 php 代码如下：

<a class="switch" data-mode="<?php /* echo Session::cookieExists("myTheme", "dark")? "dark": "light"; */?>">