IVR星号拨号计划因无效按键而无限期

Question

我是 asterisk 的新手，我正在 extensions.conf 中做拨号计划。 我正在创建一个简单的 IVR，其中客户的无效按键应仅重复两次。 之后它应该断开连接。 但这里循环无限期。 请通过检查下面的代码提供帮助

[ivr1]
exten => 100,1,Goto(ivr1,s,1)
exten => s,1,Set(VOLUME(TX)=20)
exten => s,n,Answer(500)
same => n(loop),Background(playfile)
same => n,WaitExten(10)
exten => 1,1,Dial(SIP/ivr_218/xxxx,30,m(waiting-audio))
exten => 1,2,Dial(SIP/ivr_218/xxxx,30,m(waiting-audio))
same => n,Hangup(${ActionID},keypress1)
exten => 2,1,Dial(SIP/ivr_218/xxxx,30,m(waiting-audio))
same => n,Hangup(${ActionID},keypress2)
exten => i,1,Playback(playfile_for_invalid)
same => n,Goto(s,loop)
exten => t,1,Playback(playfile_for_noresponse)
same => n,Goto(s,loop)
exten => n,Hangup()

Answer 1

你可以像这样添加计数器，

[ivr1]
exten => 100,1,Goto(ivr1,s,1)
**exten => s,1,Set(Counter = 0)**
exten => s,1,Set(VOLUME(TX)=20)
exten => s,n,Answer(500)
same => n(loop),Background(playfile)
same => n,WaitExten(10)
exten => 1,1,Dial(SIP/ivr_218/xxxx,30,m(waiting-audio))
exten => 1,2,Dial(SIP/ivr_218/xxxx,30,m(waiting-audio))
same => n,Hangup(${ActionID},keypress1)
exten => 2,1,Dial(SIP/ivr_218/xxxx,30,m(waiting-audio))
same => n,Hangup(${ActionID},keypress2)
exten => i,1,Playback(playfile_for_invalid)
**same => n,Set(Counter=$[${Counter}+1])
same => n,GotoIf($["${Counter}"<"2"]?s,loop)
same => n,Hangup()**
exten => t,1,Playback(playfile_for_noresponse)
same => n,Goto(s,loop)
exten => n,Hangup()