[英]How extract only alphanumeric characters from string? (SQL Google BigQuery)
[英]How to EXTRACT from long string by SQL BigQuery
通过使用SQL的BigQuery(#standardSQL),我想提取0.1e1和0.55e6到另一列和转换数据类型float - > Int64的。
\nsub_total:\n- !ruby/object:BigDecimal 18:0.1e1\n- !ruby/object:BigDecimal 18:0.55e6\ninvoice_number:\n- \n- '
我的预期:
字符串 | 1 | 550000
使用regexp_extract_all()
提取字符串。 然后转换为浮点数,然后转换为整数以求和:
select t.*,
(select sum(cast(cast(val as float64) as int64))
from unnest(regexp_extract_all(str, '[0-9][.][0-9]*e[0-9]+')) val
)
from (select ' \nsub_total:\n- !ruby/object:BigDecimal 18:0.1e1\n- !ruby/object:BigDecimal 18:0.55e6\ninvoice_number:\n- \n- ' as str
) t;
编辑:
如果要将这些提取到数组中,只需使用:
select t.*,
(select array_agg(cast(cast(val as float64) as int64))
from unnest(regexp_extract_all(str, '[0-9][.][0-9]*e[0-9]+')) val
) as int_array
from (select ' \nsub_total:\n- !ruby/object:BigDecimal 18:0.1e1\n- !ruby/object:BigDecimal 18:0.55e6\ninvoice_number:\n- \n- ' as str
) t
如果您想将它们放在单独的列中,只需使用数组操作。
编辑:
如果您想要单独列中的值:
select t.*, ar[safe_ordinal(1)] as col1,
ar[safe_ordinal(2)] as col2
from (select t.*,
array_agg(cast(cast(val as float64) as int64)) as ar
from (select ' \nsub_total:\n- !ruby/object:BigDecimal 18:0.1e1\n- !ruby/object:BigDecimal 18:0.55e6\ninvoice_number:\n- \n- ' as str
) t
) t
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