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[英]Mysql Query: LEFT JOIN List all orders and “balance due” for a customer, if no orders, just list customer. 3 Tables
[英]query to get customer list using JOIN with sum () of the amounts spent in orders
我有以下表格
table anag (客户注册)
id | surname | name | phone |
----------------------------------------------
1 | Brown | Jack | +3989265781 |
2 | Smith | Bill | +3954872358 |
3 | Rogers | Stan | +3912568453 |
4 | Pickford | Eric | +3948521358 |
----------------------------------------------
表级别(将每个客户与其销售人员联系起来的表。出于数据库注册的原因,客户和卖家之间的链接由客户的电话号码给出)
id | client_phone | id_seller |
--------------------------------------
1 | +3989265781 | 4 |
2 | +3954872358 | 7 |
3 | +3912568453 | 7 |
4 | +3948521358 | 8 |
--------------------------------------
表订单(当然包含客户购买的所有商品)
id | id_client | id_item | id_seller | price | status |
--------------------------------------------------------------------
1 | 1 | 2 | 4 | 12.50 | 2 |
2 | 2 | 2 | 7 | 12.50 | 2 |
3 | 2 | 3 | 7 | 10.00 | 3 |
4 | 2 | 3 | 7 | 10.00 | 3 |
5 | 2 | 4 | 7 | 20.50 | 1 |
6 | 3 | 2 | 7 | 12.50 | 1 |
7 | 3 | 5 | 7 | 19.00 | 3 |
8 | 3 | 7 | 7 | 31.00 | 2 |
9 | 4 | 1 | 8 | 5.00 | 1 |
--------------------------------------------------------------------
我想要做的是从这些表的 JOIN 中获取一个完整的列表,由他的客户的卖家按照订单状态为 2 或 3 的订单金额降序排序
像这样(示例卖家 ID 7):
id | surname | name | amaount |
----------------------------------------
3 | Rogers | Stan | 50.00 |
2 | Smith | Bill | 32.50 |
----------------------------------------
我已经尝试过这个对我来说似乎正确的查询,但不幸的是它在 fetch_assoc() 中返回错误
SELECT a.id, a.surname, a.name, o.amount FROM levels AS l
JOIN anag AS a ON a.phone = l.client_phone
JOIN {
SELECT id_client, SUM(price) AS amount FROM orders
WHERE id_seller = '7' AND (status = '2' OR status = '3') GROUP BY id_client
} AS o ON o.id_client = a.id
WHERE l.id_seller = '7'
ORDER BY o.amount DESC
如果我将子查询与主查询分开,两者都返回我期望的数据,这对我来说似乎很奇怪,两者之间的 JOIN 无法正常工作
我认为唯一真正的错误是使用花括号而不是括号:
SELECT a.id, a.surname, a.name, o.amount
FROM levels l JOIN
anag a
ON a.phone = l.client_phone JOIN
(SELECT id_client, SUM(price) AS amount
FROM orders
WHERE id_seller = '7' AND status IN ('2', '3'))
GROUP BY id_client
) o
ON o.id_client = a.id
WHERE l.id_seller = '7'
ORDER BY o.amount DESC;
此外:
IN
缩短对多个值的相等比较。status
和id_seller
看起来像数字。 如果是这样,请删除单引号。 不要混合数据类型。orders
的卖家与客户的anag
的卖家不同,您的问题是不明确的。 这可以保持您的逻辑(卖家需要匹配)。SELECT a.id, a.surname, a.name, sum(o.price) 'amount'
从阿纳格
LEFT JOIN 级别 l ON l.id =a.id
LEFT JOIN ON o.id_seller = l.id_seller AND o.id_client = l.id 的订单
按 o.id_seller 分组
按金额排序 DESC
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