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[英]how agreggate all results into 1 average from a query in prometheus promql
[英]Prometheus query promql to make average on the same field
在我的普罗米修斯数据库中,我从三个不同的主机获得了指标,我想在它们之间求平均值,这样我就可以进行聚合:
information{application=~"$app",access=~"$access",quantile="0.99", host="prom01"}
information{application=~"$app",access=~"$access",quantile="0.99", host="prom02"}
information{application=~"$app",access=~"$access",quantile="0.99", host="prom03"}
我尝试在唯一的查询命令上对这三个指标求和,然后再乘以三个,如下所示:
(information{application=~"$app",access=~"$access",quantile="0.99", host="prom01"} +
information{application=~"$app",access=~"$access",quantile="0.99", host="prom02"} +
information{application=~"$app",access=~"$access",quantile="0.99", host="prom03"})/3
但它不起作用<
此外,我尝试了 sum + rate,也不起作用
sum by (host) (rate(information{application=~"$app",access=~"$access",quantile="0.99"})[5m])
您可以执行以下操作:
(scalar(information{application=~"$app",access=~"$access",quantile="0.99", host="prom01"}) +
scalar(information{application=~"$app",access=~"$access",quantile="0.99", host="prom02"}) +
scalar(information{application=~"$app",access=~"$access",quantile="0.99", host="prom03"})
) / 3
但如果你这样做会更容易:
(sum(information{application=~"$app",access=~"$access",quantile="0.99", host=~"prom0(1|2|3)"}))
) / 3
或者干脆:
avg(information{application=~"$app",access=~"$access",quantile="0.99", host=~"prom0(1|2|3)"})
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