[英]Javascript: using foreach on multiple arrays at once
我有 2 个arrays
或更可能的NodeLists
,
const mainSlides = document.querySelectorAll('.mainSlides')
const thumbSlides = document.querySelectorAll('.thumbSlides')
目前我正在像这样迭代它们:
mainSlides.forEach(slide => {
slide.style.backgroundColor = `red`
})
thumbSlides.forEach(slide => {
slide.style.backgroundColor = `red`
})
由于它们都设置了相同的属性,即; background-color:red;
, 是否有一种速记方式可以同时遍历两个节点列表?
const mainSlides = document.querySelectorAll('.mainSlides') const thumbSlides = document.querySelectorAll('.thumbSlides') mainSlides.forEach(slide => { slide.style.backgroundColor = `red` }) thumbSlides.forEach(slide => { // slide.style.backgroundColor = `red` })
<div class="holder"> <div class="mainSlides"> some mainSlides </div> <div class="mainSlides"> some mainSlides </div> <div class="mainSlides"> some mainSlides </div> <div class="mainSlides"> some mainSlides </div> </div> <div class="holder"> <div class="thumbSlides"> some mainSlides </div> <div class="thumbSlides"> some mainSlides </div> <div class="thumbSlides"> some mainSlides </div> <div class="thumbSlides"> some mainSlides </div> </div>
是的,您可以在一个选择器中同时选择两者:
const mainAndThumbSlides = document.querySelectorAll('.mainSlides,.thumbSlides')
您可以像这样同时选择mainSlides
和thumbSlides
:
const allSlides = document.querySelectorAll('.mainSlides, .thumbSlides');
或者,如果您不想将它们一起选择(例如,如果您想进一步单独使用它们)而只想将它们一起用于此特定操作:
const allSlides = [...mainSlides, ...thumbSlides];
allSlides.forEach(slide => {
slide.style.backgroundColor = 'red';
})
您的代码已经可以在我的浏览器中运行了,但无论如何这可能会对您有所帮助:
这是访问:
mainSlides.forEach( (item, index, array) => {
array[index] = newValue;
})
看看代码片段:
const mainSlides = document.querySelectorAll('.mainSlides') const thumbSlides = document.querySelectorAll('.thumbSlides') mainSlides.forEach( (slide, index, mainSlidesReference) => { console.log("This is only for collecting variable => ", slide.style.backgroundColor) // You can named who ever you want - importanty it is third argument // Ussually called simple `array` // I give him mainSlidesReference to make clear mainSlidesReference[index].style.backgroundColor = `red`; }) thumbSlides.forEach( (slide, index, mainSlidesReference) => { console.log("This is only for collecting variable => ", slide.style.backgroundColor) // You can named who ever you want - importanty it is third argument // Ussually called simple `array` // I give him mainSlidesReference to make clear mainSlidesReference[index].style.backgroundColor = `red`; })
.holder { display:flex; } .mainSlides { background-color: black; } .thumbSlides { background-color: black; }
<div class="holder"> <div class="mainSlides"> some mainSlides </div> <div class="mainSlides"> some mainSlides </div> <div class="mainSlides"> some mainSlides </div> <div class="mainSlides"> some mainSlides </div> </div> <div class="holder"> <div class="thumbSlides"> some mainSlides </div> <div class="thumbSlides"> some mainSlides </div> <div class="thumbSlides"> some mainSlides </div> <div class="thumbSlides"> some mainSlides </div> </div>
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